我收到TypeError“ StringVar对象不可调用”

时间:2019-04-25 13:16:14

标签: python tkinter

我希望它能够将具有不同价格的不同类型添加到一个简单的GUI中,但我不断收到此回调错误 我是从前不久的一个简单的计算器复制代码,但不知道有什么不同,stringvar是否有干扰之处?

from tkinter import *

def price():
    num1 = eval(txtFirst())
    first = num1 * 22.75
    num2 = eval(txtSecond())
    second = num2 * 100
    num3 = eval(txtThird())
    third = num3 * 20.50
    num4 = eval(txtFourth())
    fourth = num4 * 90
    num5 = eval(txtFifth())
    fifth = num5 * 25.50
    num6 = eval(txtSixth())
    sixth = num6 * 125.50
    sum = first + second + third + fourth + fifth + sixth
    cost.set("Sum: " + str(sum))


window = Tk()
window.title("Chicken Feed")
window.geometry("500x500")
Label(window, text="Feed\nType:").grid(row=0, column=0)
Label(window, text="Amount:").grid(row=0,column=1)
Label(window, text="Feed\nCost:").grid(row=0, column=2)
Label(window, text="10kg Pellets:").grid(row=1,column=0)
Label(window, text="50kg Pellets:").grid(row=2,column=0)
Label(window, text="10kg Mash:").grid(row=3,column=0)
Label(window, text="50kg Mash:").grid(row=4,column=0)
Label(window, text="10kg Enhanced:").grid(row=5,column=0)
Label(window, text="50kg Pellets:").grid(row=6,column=0)


cost = StringVar()
cost = Entry(window, state='readonly', width=20, textvariable=cost)
cost.grid(row=1, column=2, columnspan=3, padx=20, pady=6)


txtFirst = StringVar()
entFirst = Entry(window, width=5, textvariable=txtFirst)
entFirst.grid(row=1, column=1)

txtSecond = StringVar()
entSecond = Entry(window, width=5, textvariable=txtSecond)
entSecond.grid(row=2, column=1)

txtThird = StringVar()
entThird = Entry(window, width=5, textvariable=txtThird)
entThird.grid(row=3, column=1)

txtFourth = StringVar()
entFourth = Entry(window, width=5, textvariable=txtFourth)
entFourth.grid(row=4, column=1)

txtFifth = StringVar()
entFifth = Entry(window, width=5, textvariable=txtFifth)
entFifth.grid(row=5, column=1)

txtSixth = StringVar()
entSixth = Entry(window, width=5, textvariable=txtSixth)
entSixth.grid(row=6, column=1)

btnAdd = Button(window, text="Calculate", width=3, command=price)
btnAdd.grid(row=2, column=2, padx=20)

window.mainloop()

在输入小部件中输入数字后,我仍然收到错误消息:

Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Luke\AppData\Local\Programs\Python\Python37\lib\tkinter\__init__.py", line 1705, in __call__
    return self.func(*args)
  File "C:\Users\Luke\Desktop\stage2.py", line 4, in price
    num1 = eval(txtFirst())
TypeError: 'StringVar' object is not callable

1 个答案:

答案 0 :(得分:1)

我认为您想做的是返回txtFirst的值。请勿为此使用eval()。要获取值:

num1 = txtFirst.get()