使用VBA进行Web抓取-HTMLDocument对象的早期绑定VS晚期绑定

时间:2019-04-25 11:06:50

标签: html excel vba web-scraping

我正在尝试基于“ https://finance.yahoo.com”设置股票价值的自动更新。

我需要使用后期绑定,该绑定不起作用,而早期绑定可以正常工作。有办法解决吗?

 Sub FetchFinanceInfoLateBinding()

    Dim XMLReq As Object
    Dim HTMLDoc As Object
    Dim post As Object, I&

    Set XMLReq = CreateObject("Msxml2.ServerXMLHTTP.6.0")
    'Set HTMLDoc = CreateObject("MSXML2.DOMDocument.6.0")
    Set HTMLDoc = CreateObject("htmlfile")

    XMLReq.Open "GET", "https://finance.yahoo.com/quote/BABA/cash-flow?p=BABA", False
    XMLReq.send
    HTMLDoc.body.innerHTML = XMLReq.responseText

    Set post = HTMLDoc.getElementsByClassName("Trsdu(0.3s) Fw(b) Fz(36px) Mb(-4px) D(ib)")(0)
    Debug.Print post.innerText


End Sub


Sub FetchFinanceInfoEarlyBinding()

    Dim XMLReq As New XMLHTTP60
    Dim HTMLDoc As New HTMLDocument
    Dim post As Object, I&

    XMLReq.Open "GET", "https://finance.yahoo.com/quote/BABA/cash-flow?p=BABA", False
    XMLReq.send
    HTMLDoc.body.innerHTML = XMLReq.responseText


    Set post = HTMLDoc.getElementsByClassName("Trsdu(0.3s) Fw(b) Fz(36px) Mb(-4px) D(ib)")(0)
    Debug.Print post.innerText

End Sub

如前所述,我希望能够在设置此解决方案时使用后期绑定。

1 个答案:

答案 0 :(得分:0)

如@omegastripes的评论中所述:

  

后期绑定的htmlfile使用低于9的IE版本,该版本不支持   .getElementsByClassName方法

不过,您可以对其进行正则表达式:

Option Explicit
Public Sub FetchFinanceInfoLateBinding()
    Dim XMLReq As Object
    Dim HTMLDoc As Object
    Dim post As Object, I&

    Set XMLReq = CreateObject("Msxml2.ServerXMLHTTP.6.0")
    Set HTMLDoc = CreateObject("htmlfile")

    XMLReq.Open "GET", "https://finance.yahoo.com/quote/BABA/cash-flow?p=BABA", False
    XMLReq.send
    HTMLDoc.body.innerHTML = XMLReq.responseText

    MsgBox GetValue(XMLReq.responseText, """regularMarketPrice"":{""raw"":[0-9.]+,""fmt"":""(\d+\.\d+)""}")

End Sub
Public Function GetValue(ByVal inputString As String, ByVal sPattern As String) As String
    With CreateObject("vbscript.regexp")
        .Global = True
        .MultiLine = True
        .IgnoreCase = False
        .Pattern = sPattern
        If .test(inputString) Then
            GetValue = .Execute(inputString).item(10).SubMatches(0)
        Else
           GetValue = vbNullString
        End If
    End With
End Function

尝试正则表达式here