Question

我正在重写equals和hashcode方法来定义对象的唯一性，但是它似乎不起作用。以下是重写equals和hashcode的代码，但它不起作用。还有什么其他方法可以删除重复项？

public class Test {

    private static class Model {

        private String firstName;
        private String lastName;

        public Model(final String firstName, final String lastName){
            this.firstName = firstName.trim();
            this.lastName = lastName.trim();
        }


        public String getFirstName() {
            return firstName;
        }

        public String getLastName() {
            return lastName;
        }

        @Override
        public String toString() {
            return MoreObjects.toStringHelper(this).add("firstName", firstName).add("lastName", lastName).toString();
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;
            Model model = (Model) o;
            return firstName.equalsIgnoreCase(model.firstName) &&
                    lastName.equalsIgnoreCase(model.lastName);
        }

        @Override
        public int hashCode() {
            return Objects.hash(firstName, lastName);
        }
    }

    public static void main(String[] args){

        final List<Model> listWithDuplicates = new ArrayList<>();
        listWithDuplicates.add(new Model("a","b"));
        listWithDuplicates.add(new Model("A","b"));
        listWithDuplicates.add(new Model("a","B "));
        listWithDuplicates.add(new Model("A","B"));

        System.out.println(new HashSet<Model>(listWithDuplicates));

    }
}

预期：[Model {firstName = a，lastName = b} 实际： [Model {firstName = a，lastName = b}，Model {firstName = A，lastName = b}，Model {firstName = a，lastName = B}，Model {firstName = A，lastName = B}]

Answer 1

您已经用equalsIgnoreCase而不是equals测试了相等性：

return firstName.equalsIgnoreCase(model.firstName) &&
       lastName.equalsIgnoreCase(model.lastName);

在hashCode和firstName中对lastName和hasdCode进行哈希处理时要考虑到用于表示字符串的确切大小写。

要使其不区分大小写，请将@Override public int hashCode() { firstName = firstName != null ? firstName.toLowerCase() : firstName; lastName = lastName != null ? lastName.toLowerCase() : lastName; return Objects.hash(firstName, lastName); }设置为小写或大写：

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无法确定唯一的对象集

1 个答案: