PHP月年日选择下拉列表以在中间件Laravel中生成日期格式

Question

我在出生日期，日，月和年中有3个字段，作为3个下拉列表。我想将它们存储在数据库的单个Date_of_birth列中。

如何在中间件中解决该问题？

尝试

public function dob($request, Closure $next) {
    $dobrequest -> all();
    if (isset($dobrequest['day'] && $dobrequest['month'] &&                $dobrequest['year'])) {
        $dobrequest['dob'] = $dobrequest['day']."/".$dobrequest['month']."/". $dobrequest['year'];            
    }
    $request ->replace($dobrequest);
    return $next($request);
}

register.blade.php

<div class="col-md-6 pull-left" style="padding-left:0px;">
   <font size="3">  <label for="dob">Date of Birth</label><br class="clearfix" />
      <div class="form-group clearfix">
          <label for="dob_month" class="sr-only">Month</label>
                  <select name = "dob" id="m" class="form-control">
                     <option>Month</option>
                      @for ($month = 1; $month <= 12; $month++)                  <option value = "{{ $month }}">{{ $month }}</option>                   @endfor
                    </select>
      </div>
      <div class="form-group">
            <label for="dob_day" id="d" class="sr-only">Day</label>
                  <select name = "dob" class="form-control">
                      <option>Day</option>
                        @for ($day = 1; $day <= 31; $day++)                    <option value = "{{ $day }}">{{ $day }}</option>                    @endfor
                  </select>
      </div>
      <div class="form-group">
            <label for="dob_year" id="y" class="sr-only">Year</label>
                  <select name = "dob" class="form-control">
                       <option>year</option>
                      @for ($year = 1950; $year <= 2052 ; $year++)                  <option value = "{{ $year }}">{{ $year }}</option>                  @endfor
                  </select>
      </div>

    </font>
  </div>

registercontroller.php

protected function create(array $data)
    {

       dd($data);

        return User::create([
            'fname' => $data['fname'],
            'lname' => $data['lname'],
            'email' => $data['email'],
            'zipcode' => $data['zipcode'],
            'password' => Hash::make($data['password']),
            'gender' => $data['gender'],
            'dob' => $data['day'],$data['month'],$data['year'],
            'health' => $data['health'],
        ]); 

    }

模型-> user.php

受保护的$ fillable = [         'fname'，'lname'，'email'，'zipcode'，'password'，'gender'，'dob'，'health'，     ];

迁移

Class CreateUsersTable扩展了迁移 {     / **      *运行迁移。      *      * @返回无效      * /     公共功能up（）     {         Schema :: create（'users'，function（Blueprint $ table）{             $ table-> bigIncrements（'id'）;             $ table-> string（'fname'）;             $ table-> string（'lname'）;             $ table-> string（'email'）-> unique（）;             $ table-> timestamp（'email_verified_at'）-> nullable（）;             $ table-> string（'zipcode'）;             $ table-> string（'password'）;             $ table-> string（'gender'）;             $ table-> DATE（'dob'）;             $ table-> string（'health'）;             $ table-> rememberToken（）;             $ table-> timestamps（）;         }）;     }

];

Answer 1

您可以创建将日期，日期和年份字符串格式化为日期格式的帮助器类 并定义如下功能：

public function formatDate($year, $month, $day) {
   return strftime("%F", strtotime($year."-".$month."-".$day));
}

Answer 2

public function handle($request, Closure $next)
    {
        $dobrequest = $request->all();
        if(isset($dobrequest['year']) && isset($dobrequest['month']) && isset($dobrequest['day'])){
            $dobrequest['dob'] = $dobrequest['year'].'-'.$dobrequest['month'].'-'. $dobrequest['day']; 
        }
        $request->replace($dobrequest);
        return $next($request);
    }
}

Answer 3

您可以使用参数天和年字符串创建包装函数，并定义如下函数：

function wrapDate($day, $month, $year) {
    return sprintf("%d/%d/%d", $day, $month, $year);
}