Question

我尝试将重复值连接到数组中，但是如果连接的数组具有不同的值，则应该自动创建另一个数组。

这是我的代码，在laravel上使用查询生成器

DB::table('users')
    ->select(
        'users.id',
        'users.first_name',
        'users.last_name',
        'users.no_rekening',
        'users.empid',
        'users.no_rekening',
        'users.detail',
        'users.is_approve',
        'users.is_active',
        'karyawan_project.project_id',
        'project.nama as nama_project',
        'client.nama as nama_client'
    )->leftJoin(
        'karyawan_project',
        'users.id','=','karyawan_project.karyawan_id',
        'client.nama '
    )->join(
        'project',
        'karyawan_project.project_id','=','project.id'
    )->join('spk','project.spk_id','=','spk.id')
    ->join('client','spk.client_id','=','client.id')
    ->where('tipe', 2)
    ->whereIn('is_active', [1,0,2])
    ->orderBy('users.id')
    ->get();

和结果

1 => {#747 ▼
  +"id": 17
  +"first_name": "Dadan R"
  +"last_name": "Hadiansyah"
  +"no_rekening": "1150006713467"
  +"empid": "01180104"
  +"detail": ""
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 4
  +"nama_project": "Driver Manager & Operasional"
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"
}
2 => {#797 ▼
  +"id": 18
  +"first_name": "Setia"
  +"last_name": "Darma"
  +"no_rekening": "1150006713475"
  +"empid": "01180105"
  +"detail": null
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 181
  +"nama_project": "Driver Operasional"
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"
}
3 => {#790 ▼
  +"id": 18
  +"first_name": "Setia"
  +"last_name": "Darma"
  +"no_rekening": "1150006713475"
  +"empid": "01180105"
  +"detail": null
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 4
  +"nama_project": "Driver Manager & Operasional"
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"
}
4 => {#796 ▼
  +"id": 18
  +"first_name": "Setia"
  +"last_name": "Darma"
  +"no_rekening": "1150006713475"
  +"empid": "01180105"
  +"detail": null
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 6
  +"nama_project": "PENGAMANAN STATION MBK"
  +"nama_client": "PT. PERMATA GRAHA NUSANTARA"
}
5 => {#757 ▼
  +"id": 19
  +"first_name": "Ardian"
  +"last_name": "Ismail"
  +"no_rekening": "1150004433837"
  +"empid": "01180106"
  +"detail": null
  +"is_approve": 1
  +"is_active": 0
  +"project_id": 4
  +"nama_project": "Driver Manager & Operasional"
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"

结果具有重复的值，其中id = 18，并且具有不同的nama_project

我想要的是，具有重复值的id连接到一个数组中以及具有不同值的nama_project

喜欢

1 => {#747 ▼
  +"id": 17
  +"first_name": "Dadan R"
  +"last_name": "Hadiansyah"
  +"no_rekening": "1150006713467"
  +"empid": "01180104"
  +"detail": ""
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 4
  +"nama_project": "Driver Manager & Operasional"
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"
}
2 => {#797 ▼
  +"id": 18
  +"first_name": "Setia"
  +"last_name": "Darma"
  +"no_rekening": "1150006713475"
  +"empid": "01180105"
  +"detail": null
  +"is_approve": 1
  +"is_active": 1
  +"project_id": 181
  +"nama_project": ▼{
                 +"Driver Operasional"
                 +"Driver Manager & Operasional"
                 +"PENGAMANAN STATION MBK"
               }
  +"nama_client": "PT. TRANSPORTASI GAS INDONESIA"
}

Answer 1

由于您已按users.id订购结果。假设您将结果保存在$users中，则可以执行以下操作：

$usersWithMergedProjects = [];
$previous_id = 0;
foreach($users as $user){
    if($user->id == $previous_id){
        array_push($usersWithMergedProjects[$user->id]->nama_projects, $user->nama_project);
    } else {
        $usersWithMergedProjects[$user->id] = $user;
        $usersWithMergedProjects[$user->id]->nama_projects = [];
        array_push($usersWithMergedProjects[$user->id]->nama_projects, $user->nama_project);

    }
    $previous_id = $user->id;
    unset($usersWithMergedProjects[$user->id]->nama_project);
}

注意：如果对此有任何错误，请对错误进行截图。

Answer 2

我找到了答案

$data = DB::table('users')
                  // ->with(['history'=>function($kar){
                  //             $kar->with('project.spk.client')->select('project_id','karyawan_id')->where('status',1);
                  //  }])
                        ->select('users.id','users.first_name','users.last_name','users.no_rekening','users.empid','users.no_rekening',
                                 'users.detail','users.is_approve','users.is_active','karyawan_project.project_id','karyawan_project.status',
                                 'project.nama as nama_project',
                                 'client.description as nama_client')
                        ->leftJoin('karyawan_project', 'users.id','=','karyawan_project.karyawan_id')
                        ->join('project','karyawan_project.project_id','=','project.id')
                        ->join('spk','project.spk_id','=','spk.id')
                        ->join('client','spk.client_id','=','client.id')
                        ->where('tipe', 2)->whereIn('is_active',[1,0,2])->orderBy('users.id')->get()
               ;

               $previous_id = 0;

               foreach($data as $key => $user){
                     $user->merged = [];
                     $user->project = '<b>'.$user->nama_client. '</b> ' . $user->nama_project;
                     if ($previous_id == $user->id) {

                           $minKey = $key-1;

                           if (!empty($data[$minKey]->merged)) {

                                 if ($user->status == 1) {
                                       array_push($user->merged, $user->project);
                                 }

                                    $user->merged = array_merge($user->merged, $data[$minKey]->merged);


                             }else {
                                   if ($user->status == 1) {
                                          array_push($user->merged, $user->project, $data[$minKey]->project);
                                   }

                            }
                       unset($data[$minKey]);

                       }else {
                               if ($user->status == 1) {
                                     array_push($user->merged,$user->project);
                               }
                       }
                       $previous_id = $user->id;
               }


            $data = $data->sortBy('first_name');

如果值重复则连接数组（Laravel）

2 个答案: