我有一个查询,其中列sb.start_time AS shift_date
和MIN(cs.start_time) AS first_completed_shift
返回的值存储为时间戳,但我希望格式仅为dd-mm-yyyy
SELECT DISTINCT
sb.start_time AS shift_date, --I want this as dd-mm-yyyy format
i.title AS industry,
wl.name AS venue_name,
w.first_name,
w.last_name,
MIN(cs.start_time) AS first_completed_shift, --I want this as dd-mm-yyyy format
i.title AS industry,
w.interviewed_on AS induction_date,
d.issue_date AS edbs_issue_date,
d.created_at AS date_dbs_added,
a.user_id
FROM shift_bookings sb
JOIN jobs j ON sb.job_id = j.id
JOIN listings l ON j.listing_id = l.id
JOIN work_locations wl ON l.venue_id = wl.id
JOIN workers w ON sb.worker_id = w.id
JOIN completed_shifts cs ON w.id = cs.worker_id
JOIN documents d ON w.id = d.documentable_id
JOIN audits a ON d.id = a.auditable_id
JOIN industries i ON j.industry_id = i.id
WHERE sb.shift_id IN (253106)
AND d.document_type_id = 33
AND a.auditable_type = 'Document'
GROUP BY
sb.start_time,
wl.name,
w.first_name,
w.last_name,
i.title,
w.interviewed_on,
d.issue_date,
d.created_at,
a.user_id
答案 0 :(得分:0)
如果您想要一个合适的date
值,则将时间戳转换为日期:
sb.start_time::date AS shift_date
然后您需要调整group by
。
和
MIN(cs.start_time::date) AS first_completed_shift
您还可以使用to_char()
将时间戳记格式化为所需的任何格式。