ValueError:以10为底的int()的无效文字:b'3 \ n1 \ n \ n'

时间:2019-04-24 16:57:21

标签: python

我的代码有问题,我有一个TCP连接,我是客户端,收到的数字如下:

1
4
6
3
..

(我收到的数字仅为:1、2、3、4、5、6、7)以随机顺序排列。 我得到的错误是:ValueError:以10为底的int()的无效文字:b'2 \ n6 \ n \ n'。

引用此部分的代码是:

# TCP connection
try:
    so = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
except socket.error as err:
    print ("socket creation failed with error %s" %(err))

# default port for socket
port = 2000

# default time out
so.settimeout(1000000)

try:
    host_ip = socket.gethostbyname('localhost')
except socket.gaierror:
    # this means could not resolve the host
    print ("there was an error resolving the host")
    sys.exit()

# connecting to the server
so.connect((host_ip,port))

# MATLAB INFORMATION FOR OFFLINE EXPERIMENT
Nepoch = 10  #nr de epochs por trial
Nwords = 7   #nr de palavras (SIM, NAO, FOME, SEDE, URINAR, AR, POSICAO)
SeqTrain = [1, 3, 5, 7, 2, 4, 6, 1, 3, 5, 7, 2, 4, 6] #sequencia offline de treino

# read the TCP sequence received
def sequencia():
    num = 0
    for i in range(0,999):
        s = so.recv(port) + b'\n' #since the sequence received is : 1\n 2\n 5\n etc
        i = int(s)
        #feedbak offline (for the user to know which are the words)
        if (num in (0, Nepoch*Nwords+1, Nepoch*Nwords*2+2, Nepoch*Nwords*3+3, Nepoch*Nwords*4+4, Nepoch*Nwords*5+5,\
                    Nepoch*Nwords*6+6)):
            labels1[i-1].configure(foreground="white")
            root.update()
        elif (num in (Nepoch*Nwords*7+7, Nepoch*Nwords*8+8, Nepoch*Nwords*9+9, Nepoch*Nwords*10+10,\
                     Nepoch*Nwords*11+11, Nepoch*Nwords*12+12, Nepoch*Nwords*13+13)):
            labels2[i-1].configure(foreground="white")
            root.update()
        else:
            labels[i-1].configure(background="green",foreground="red")
            root.update()
            winsound.PlaySound(sounds[i-1], winsound.SND_FILENAME)
            labels[i-1].configure(background="gray",foreground="white")
            root.update()
        num = num + 1

其中的一部分是错误的:第44行:i = int(s)。 您有什么想法我可以解决这个问题吗?非常感谢

1 个答案:

答案 0 :(得分:0)

这里:

so.recv(port)

您收到的电话号码不只一个。试试:

s = so.recv(port)
for i in [int(n) for n in s.split(b'\n') if n]:
    ...