我有一批货物,并且在阵列上运行一个循环以查找具有多个包裹的货物,因此我可以将它们克隆到一个新阵列中。我需要处理运输标签,该标签在阵列中每个对象上产生一个标签。
我添加了一个新的键/值对,以显示计数器中的单个包裹编号,但是我所有的“袋索引”都使用相同的编号
// Function to sort the concatenated array
function compare( a, b ) {
if ( a["SNAP ID"] < b["SNAP ID"] ){
return -1;
}
if ( a["SNAP ID"] > b["SNAP ID"] ){
return 1;
}
return 0;
}
// Demo shipments array
var shipments = [{
"SNAP ID": "1234567890",
"FULL NAME": "Person 1",
"PACKAGE QTY": 5
},
{
"SNAP ID": "0987654321",
"FULL NAME": "Person 2",
"PACKAGE QTY": 2
},
{
"SNAP ID": "5432167890",
"FULL NAME": "Person 3",
"PACKAGE QTY": 3
}
];
// Empty array which will contain cloned shipment objects
var data = [];
// Running loop on the shipments array
for (var i = 0; i < shipments.length; i++) {
var Pkg = shipments[i]["PACKAGE QTY"]
var shipment = shipments[i]
shipment["BAG INDEX"] = 1
// Running loop on the shipments containing more the 1 packages
if (Pkg > 1) {
for (var k = 0; k < (Pkg - 1); k++) {
data.push(shipment);
shipment["BAG INDEX"] += 1;
};
};
};
var complete = shipments.concat(data);
var sorted = complete.sort(compare);
console.log(sorted);
这就是我要回来的
0: {SNAP ID: "0987654321", FULL NAME: "Person 2", PACKAGE QTY: 2, BAG INDEX: 2}
1: {SNAP ID: "0987654321", FULL NAME: "Person 2", PACKAGE QTY: 2, BAG INDEX: 2}
2: {SNAP ID: "1234567890", FULL NAME: "Person 1", PACKAGE QTY: 5, BAG INDEX: 5}
3: {SNAP ID: "1234567890", FULL NAME: "Person 1", PACKAGE QTY: 5, BAG INDEX: 5}
4: {SNAP ID: "1234567890", FULL NAME: "Person 1", PACKAGE QTY: 5, BAG INDEX: 5}
5: {SNAP ID: "1234567890", FULL NAME: "Person 1", PACKAGE QTY: 5, BAG INDEX: 5}
6: {SNAP ID: "1234567890", FULL NAME: "Person 1", PACKAGE QTY: 5, BAG INDEX: 5}
7: {SNAP ID: "5432167890", FULL NAME: "Person 3", PACKAGE QTY: 3, BAG INDEX: 3}
8: {SNAP ID: "5432167890", FULL NAME: "Person 3", PACKAGE QTY: 3, BAG INDEX: 3}
9: {SNAP ID: "5432167890", FULL NAME: "Person 3", PACKAGE QTY: 3, BAG INDEX: 3}
length: 10
答案 0 :(得分:2)
您必须创建对象的副本。否则,您还将为已经添加到BAG INDEX
数组中的对象增加data
。
只需使用:
data.push(Object.assign({}, shipment));
答案 1 :(得分:0)
您需要在此处创建一个新对象:
if (Pkg > 1) {
for (var k = 0; k < (Pkg - 1); k++) {
data.push(shipment);
shipment["BAG INDEX"] += 1;
};
};
否则,您只是在同一个装运对象上进行操作。