Question

如果一个用户达到一定的金额，我对此游戏有多个条件，那么如果另一个用户处于同等水平，他们会偷走更多的钱。

我在尝试弄清楚逻辑时遇到问题。我添加了一些评论，提出了问题，但我只是不知道是否有一种更简单的方法来处理这种事情。

启动if语句时是从较低的值开始还是应该从较大的值开始？

# do I need to put a check and money(message.author) < 500000 here?
if money(message.author) >= 20000 and money(user) < 20000: 
    do_thing1()
# do I need to put a check and money(user) < 500000 here?
elif money(message.author) < 20000 and money(user) >= 20000: 
    do_thing1()
# do I need to put a check money(message.author) and money(user) < 500000 here?
elif money(message.author) >= 20000 and money(user) >= 20000: 
    do_thing2()
# do I need to put a check and money(user) >= 20000 here?
elif money(message.author) >= 500000 and money(user) < 500000: 
    do_thing2()
# do I need to put a check and money(message.author) >= 20000 here?
elif money(message.author) < 500000 and money(user) >= 500000: 
    do_thing2()
elif money(message.author) >= 500000 and money (user) >= 500000: 
    do_thing3()

Answer 1

请注意，如果两者均小于20000，或者两者均大于20000但小于500000，则不会显示会发生什么。在下面处理。

if money(message.author) < 20000 and money(user) < 20000:
    do_thing0()  # both have < 20000. You didn't show this case.
elif money(message.author) < 20000 or money(user) < 20000:
    do_thing1()  # only one of them has < 20000
elif money(message.author) < 500000 and money(user) < 500000:
    do_thingX()  # both have >= 20000 but < 500000. You didn't show this case.
elif money(message.author) < 500000 or money(user) < 500000:
    do_thing2()  # both have >= 20000, only one of them has < 5000000
else:
    do_thing3()  # both have >= 500000

如果您不关心两个都有< 20000或两个都有>= 20000 and < 500000的情况，则可以使用独占ors来缩短它：

elif money(message.author) < 20000 ^ money(user) < 20000:
    do_thing1()  # only one of them has < 20000
elif money(message.author) < 500000 ^ money(user) < 500000:
    do_thing2()  # both have >= 20000, only one of them has < 5000000
elif money(message.author) >= 500000 and money(user) >= 50000
    do_thing3()  # both have >= 500000

请注意，在最后一种情况下，我们需要明确表示，否则，我们将捕获前两种情况未捕获的任何内容，这里我假设您不想举例来说，两者都小于20000。

您的代码按顺序执行，因此，如果您通过了其中一项检查，就可以告诉您有关所处范围的信息，并且可以相应地调整逻辑。

例如，一旦完成elif money(message.author) < 500000 and ...检查，您就会知道money(message.author) >= 20000 和 money(user) >= 20000都是因为您不会到目前为止，如果那不是真的。

Answer 2

[r in dict2[str_col] for r in dict1[str_col]]

是的，您确实会这样做，否则您的某些情况将包括其他情况，例如，如果# Do I need to put a check and money(message.author) < 500000 here?和money(message.author) == 500001，您可能希望money(user) == 1发生，但它将触发{{ 1}}。

您可以将它们用于比较链，例如代替

dothing2

您可以使用更短的

dothing1

此外，定义两个临时变量if money(message.author) >= 20000 and money(message.author) < 500000 and money(user) < 20000: dothing1和if 20000 <= money(message.author) < 500000 and money(user) < 20000: dothing1可能会大大提高可读性。给定大量的ma = money(message.author)和mu = money(user)语句，您甚至可以定义if，elif等，但这可能是过大了。您还可以定义变量ma1 = ma < 20000和ma2 = 20000 <= ma < 500000，以防止输入错误（是四个零或五个？），并使其在将来更容易更改。

low = 20000

如果Elif大于，小于逻辑

2 个答案: