我正在根据某些用户输入条件从数据库中回显表单。表单将包含2个按钮。我已经成功完成了。我只是想样式化表单中的按钮(用于进一步步骤的按钮)。我不知道如何在php表单内设置按钮样式。
$result = $conn->query ($sql);
if($result ->num_rows>0){
echo '<table >';
while($row = $result ->fetch_assoc()){
echo '<tr><th>Romm Number</th>';
echo '<td >' . $row['Number']. '</td></tr>';
echo '<tr><th>Room Temperature</th>';
echo '<td >' . $row['TEMP']. '</td></tr>';
//wanna style following form buttons
echo "<form action = 'script.php' method =post>";
echo '<tr>';
echo "<td > "." <input type=submit name=alarm value=Alarm> "." </td>";
echo "<td >"." <input type=hidden name=view value ='A'> "." </td>";
echo "</tr>";
echo "</form>";
echo "<form action = 'script2.php' method =post>";
echo '<tr>';
echo "<td >"." <input type=submit name=control value='Log'> "." </td>";
echo "<td >"." <input type=hidden name=graph value ='B'> "." </td>";
echo "</tr>";
echo "</form>";
}
echo "</table>";
mysqli_free_result($result);
}else {
echo "no result";
}
//mysqli_free_result($result);
$conn->close();
}
关于在php表中设置表单按钮样式的任何建议吗?
答案 0 :(得分:2)
您可以在
之类的html标签中简单地使用样式echo "<td >"." <input type='submit' name=control value='Log' style='color:yellow;font-size:20px;border:none' class="submit"> "." </td>";
(或)
在按钮上添加特定的类并为其编写CSS,例如:
.submit {
color: red;
}