Question

需要解决这个问题

这是针对REST API的，我需要对每一行进行计数，以便可以将其用于分页。

SELECT *
FROM   (SELECT ROW_NUMBER()
                 OVER (
                   ORDER BY sc.LEGACY_PARTY_ID) AS rownum,
               *
        FROM   (SELECT *,
                       ROW_NUMBER()
                         OVER (
                           ORDER BY sc.LEGACY_PARTY_ID) AS rownuminner
                FROM   (SELECT *
                        FROM   (SELECT sc.legacy_party_id,
                                       sc.practice,
                                       sr.risk_level
                                FROM   dbo.supplier sc
                                INNER JOIN dbo.risk sr
                                  ON sc.LEGACY_PARTY_ID = sr.LEGACY_PARTY_ID)AS z) AS a)AS c
        WHERE  rownuminner <= ?)c
WHERE  rownum > ?;

需要每行具有row_number的表元素，但会出现此错误：

Msg 4104，第16级，状态1，第21行
  无法绑定多部分标识符“ sc.LEGACY_PARTY_ID”。

Msg 4104，第16级，状态1，第20行
  无法绑定多部分标识符“ sc.LEGACY_PARTY_ID”。

Answer 1

您正试图通过子查询中的别名引用对象。您需要使用正确的别名来引用它：

SELECT *
FROM (SELECT ROW_NUMBER() OVER (ORDER BY c.LEGACY_PARTY_ID) AS rownum,
             *
      FROM (SELECT *,
                   ROW_NUMBER() OVER (ORDER BY a.LEGACY_PARTY_ID) AS rownuminner
            FROM (SELECT *
                  FROM (SELECT sc.legacy_party_id,
                               si.supplier_name,
                               si.supplier_description,
                               sc.practice,
                               sc.category,
                               sc.subcategory,
                               sui.industry,
                               sr.risk_level
                        FROM mip.supplier_classification AS sc
                             INNER JOIN mip.supplier_info AS si ON si.legacy_party_id = sc.LEGACY_PARTY_ID
                             INNER JOIN mip.SUPPLIER_INDUSTRY AS sui ON sc.LEGACY_PARTY_ID = sui.LEGACY_PARTY_ID
                             INNER JOIN mip.SUPPLIER_RISK AS sr ON sc.LEGACY_PARTY_ID = sr.LEGACY_PARTY_ID) AS z ) AS a ) AS c
      WHERE rownuminner <= 10) AS c
WHERE rownum > 5;

这似乎仍然太复杂了。看起来，它可能写得更简单：

WITH CTE AS
    (SELECT sc.legacy_party_id,
            si.supplier_name,
            si.supplier_description,
            sc.practice,
            sc.category,
            sc.subcategory,
            sui.industry,
            sr.risk_level,
            ROW_NUMBER() OVER (ORDER BY sc.legacy_party_id) AS RN
     FROM mip.supplier_classification AS sc
          INNER JOIN mip.supplier_info AS si ON si.legacy_party_id = sc.LEGACY_PARTY_ID
          INNER JOIN mip.SUPPLIER_INDUSTRY AS sui ON sc.LEGACY_PARTY_ID = sui.LEGACY_PARTY_ID
          INNER JOIN mip.SUPPLIER_RISK AS sr ON sc.LEGACY_PARTY_ID = sr.LEGACY_PARTY_ID)
SELECT *
FROM CTE
WHERE RN <= ?
  AND RN > ?;

Answer 2

SELECT *
FROM   (SELECT ROW_NUMBER()
                 OVER (
                   ORDER BY c.LEGACY_PARTY_ID) AS rownum,
               *
        FROM   (SELECT *,
                       ROW_NUMBER()
                         OVER (
                           ORDER BY c.LEGACY_PARTY_ID) AS rownuminner
                FROM   (SELECT *
                        FROM   (SELECT sc.legacy_party_id,
                                       si.supplier_name,
                                       si.supplier_description,
                                       sc.practice,
                                       sc.category,
                                       sc.subcategory,
                                       sui.industry,
                                       sr.risk_level
                                FROM   mip.supplier_classification sc
                                       INNER JOIN mip.supplier_info si
                                               ON si.legacy_party_id = sc.LEGACY_PARTY_ID
                                       INNER JOIN mip.SUPPLIER_INDUSTRY sui
                                               ON sc.LEGACY_PARTY_ID = sui.LEGACY_PARTY_ID
                                       INNER JOIN mip.SUPPLIER_RISK sr
                                               ON sc.LEGACY_PARTY_ID = sr.LEGACY_PARTY_ID)AS z) AS a)AS c
        WHERE  rownuminner <= ?)c
WHERE  rownum > ?;

您已经为外部查询和使用sc定义了c别名，所以它给出了错误

SQL语法错误：无法为ROW_NUMBER（）绑定多部分标识符

2 个答案: