我正在运行固定效果面板回归,并想测试工具的有效性:
xtivreg deltahealth years years2 marpart logass logdebt smokesn vigact3 i.time ///
(RS RL = betw6265 under62 eps1 eps2 eps1u62 eps2b6265), fe vce(cluster idhhpn)
xtoverid
但是,这不起作用,因为我得到以下错误:
2b:运算符无效
如何解决此问题?
答案 0 :(得分:3)
社区贡献命令xtoverid
不支持因子变量表示法。
但是,您可以首先使用fvrevar
命令进行连续变量和虚拟变量的前缀xi
的交互:
. webuse nlswork, clear
(National Longitudinal Survey. Young Women 14-26 years of age in 1968)
. tsset idcode year
panel variable: idcode (unbalanced)
time variable: year, 68 to 88, but with gaps
delta: 1 unit
. fvrevar c.age#c.age
. xi: xtivreg ln_w age `r(varlist)' not_smsa (tenure = union south), fe
Fixed-effects (within) IV regression Number of obs = 19,007
Group variable: idcode Number of groups = 4,134
R-sq: Obs per group:
within = . min = 1
between = 0.1304 avg = 4.6
overall = 0.0897 max = 12
Wald chi2(4) = 147926.58
corr(u_i, Xb) = -0.6843 Prob > chi2 = 0.0000
------------------------------------------------------------------------------
ln_wage | Coef. Std. Err. z P>|z| [95% Conf. Interval]
-------------+----------------------------------------------------------------
tenure | .2403531 .0373419 6.44 0.000 .1671643 .3135419
age | .0118437 .0090032 1.32 0.188 -.0058023 .0294897
__000000 | -.0012145 .0001968 -6.17 0.000 -.0016003 -.0008286
not_smsa | -.0167178 .0339236 -0.49 0.622 -.0832069 .0497713
_cons | 1.678287 .1626657 10.32 0.000 1.359468 1.997106
-------------+----------------------------------------------------------------
sigma_u | .70661941
sigma_e | .63029359
rho | .55690561 (fraction of variance due to u_i)
------------------------------------------------------------------------------
F test that all u_i=0: F(4133,14869) = 1.44 Prob > F = 0.0000
------------------------------------------------------------------------------
Instrumented: tenure
Instruments: age __000000 not_smsa union south
------------------------------------------------------------------------------
命令xtoverid
将按预期工作:
. xtoverid
Test of overidentifying restrictions:
Cross-section time-series model: xtivreg fe
Sargan-Hansen statistic 1.372 Chi-sq(1) P-value = 0.2415