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Question

我有一个简单的POST：

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <math.h>

#define NEWLINE() printf("\n");
#define DIVIDER() printf("============================================================================\n");
#define PL(l) printf("LINE: %s\n", l);

int const MAX_PROCESSES = 20;
int const BUFFER_SIZE = 1024;

int exhaustedLine(char* line) {
    if (line[sizeof line - 1] == '\0' && line[sizeof line - 2] != '\n') {
        printf("n:%c 0:%c\n", line[sizeof line - 2], line[sizeof line - 1]);
        NEWLINE();
        return -1;
    }
    return 0;   
}

int main(int argc, char const *argv[]) {
    FILE* fp = popen("ps -ev", "r");
    char buf[BUFFER_SIZE];
    char* line = (char*)1;

    while (line) {
        DIVIDER();
        line = fgets(buf, BUFFER_SIZE, fp);
        PL(line);
        if (exhaustedLine(line) != 0) {
            printf("END OF LINE\n");
        }
    }

    return 0;
}

我必须支持UTF-8编码，而String url = "https://mysite"; try (CloseableHttpClient httpClient = HttpClients.custom().build()) { URIBuilder uriBuilder = new URIBuilder(url); HttpPost request = new HttpPost(); List<NameValuePair> nameValuePairs = new ArrayList<>(params); request.setEntity(new UrlEncodedFormEntity(nameValuePairs, StandardCharsets.UTF_8.name())); String encodedAuthorization = URLEncoder.encode(data, StandardCharsets.UTF_8.name()); request.addHeader("Authorization", encodedAuthorization); try (CloseableHttpResponse response = httpClient.execute(request)) {编码还不够，但是尚不清楚必须执行以下几种操作必须

使用UrlEncodedFormEntity：

uriBuilder.setCharset

使用HttpPost request = new HttpPost(uriBuilder.setCharset(StandardCharsets.UTF_8)).build());参数：

http.protocol.content-charset

或者仅添加Content-Type"` header：

HttpPost request = new HttpPost(uriBuilder.setParameter("http.protocol.content-charset", "UTF-8").build());

或使用request.getParams()：

request.setHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");

还是我忽略了其他明显的解决方案？

Answer 1

// Method to encode a string value using `UTF-8` encoding scheme
private static String encodeValue(String value) {
    try {
        return URLEncoder.encode(value, StandardCharsets.UTF_8.toString());
    } catch (UnsupportedEncodingException ex) {
        throw new RuntimeException(ex.getCause());
    }
}

public static void main(String[] args) {
    String baseUrl = "https://www.google.com/search?q=";

    String query = "Hellö Wörld@Java";
    String encodedQuery = encodeValue(query); // Encoding a query string

    String completeUrl = baseUrl + encodedQuery;
    System.out.println(completeUrl);
}

}

输出

https://www.google.com/search?q=Hell%C3%B6+W%C3%B6rld%40Java

我认为这可能是解决方案。

您已经在上面提到：https://www.urlencoder.io/java/

Answer 2

要正确编码，我将在List<NameValuePair>上使用URIBuilder中的参数

然后使用

进行编码

URLEncodedUtils.format(nameValuePairs, StandardCharsets.UTF_8.name());

如何编码UTF-8 CloseableHttpClient请求

2 个答案:

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