Question

这是我的对象数组。因此，我想从中过滤出一组对象并制成另一个对象数组。

    employees = [
    {
        {
            name: "tom",
            age : 22,
            address: "moscow",
            gender: "male"
        },
        {
            name: "tom",
            age : 25,
            address: "manila",
            gender: "male"
        },
        {
            name: "tom",
            age : 21,
            address: "delhi",
            gender: "female"
        },
        {
            name: "tom",
            age : 20,
            address: "cydney",
            gender: "female"
        }
    }
    ]

例如：想想我是否要过滤属于male类别的员工并创建一个名为male_employees的新数组，那么我该怎么做。

    male_employees = [
    {
        {
            name: "tom",
            age : 22,
            address: "moscow",
            gender: "male"
        },
        {
            name: "tom",
            age : 25,
            address: "manila",
            gender: "male"
        }

    }
    ]

Answer 1

正如某人评论的那样，只看一下.filter（）函数，这里有很多关于如何使用它的示例。

您的情况如下：

 male_employees = employees.filter(employee=>employee.gender==="male")

Answer 2

尝试一下

male_employees_list = employees.filter(male_employee => male_employee.gender==="male")

如何从打字稿中的对象数组中过滤对象

2 个答案: