Question

我试图弄清楚luxon为什么无法解析此日期格式。

这是我的原始值：# normal function definition # def function(): string = "string" print(string) # multi-line # new_func = """ def do_stuff(): string = 'strung' # I don't know how to include the other line here print(string)""" # single line, note the presence of \n AND \t # new_func2 = "def do_stuff2():\n\tstring = 'strong'\n\tprint(string)\n" new_code = compile(new_func, "", 'exec') new_code2 = compile(new_func2, "", 'exec') eval(new_code) eval(new_code2) function() do_stuff() do_stuff2()。

这是什么格式（看起来像iso格式）。

代码段：

import pandas as pd
import bs4 as bs4
import requests
from requests_html import HTMLSession


if __name__ == "__main__":

    my_url = "https://ru.wikipedia.org/wiki/%D0%9C%D0%B5%D0%B6%D0%B4%D1%83%D0%BD%D0%B0%D1%80%D0%BE%D0%B4%D0%BD%D1%8B%D0%B9_%D0%B8%D0%BD%D0%B4%D0%B5%D0%BA%D1%81_%D1%81%D1%87%D0%B0%D1%81%D1%82%D1%8C%D1%8F"
    session = HTMLSession()
    my_page = session.get(my_url)

    data = pd.read_html(my_page.text, flavor="bs4", header=0)
    for item in data:
        print(item)

以上代码段的输出：

2019-04-23T23:15:07.910Z

Answer 1

啊，终于明白了。原来2019-04-23T23:15:07.910Z实际上是一个JavaScript日期对象。

这意味着我需要做const fromJSDate = DateTime.fromIJSDate(document.lastUpdatedAt)

Luxon无法解析此日期格式

1 个答案: