Question

下面的php提取我的csv文件并输出到JSON文件。

<?php

    echo "<h2>Uploading....</h2>";

    $fh = fopen("assets/files/locationsCSV.csv", "r");

    $csvData = array();

    while (($row = fgetcsv($fh, 0, ",")) !== FALSE) {
        $csvData[] = $row;
    }
    // echo json_encode($csvData);
    file_put_contents("assets/files/locationsCSV.json",json_encode($csvData))      

?>

我的json文件中的JSON如下所示：当前输出：

["Zipcode","City","Primary State","SS","County"], # only prints once
["24553","","Virginia","49050","Appomattox"], # then just this 
["24553","","Virginia","49140","Buckingham"], # etc

如何获取这样的输出/使用邮政编码列作为对象标题重新格式化？

所需的JSON输出：

{ 
 ZipCode: 24553, { 
 City: , 
 Primary State: Virginia, 
 SS: 49050,
 County: Appomattox
}

Answer 1

您需要将CSV文件的第一行读取到keys数组中，并将这些键与循环中的每一行数据结合起来：

$csvData = array();
$keys = fgetcsv($fh, 0, ",");
while (($row = fgetcsv($fh, 0, ",")) !== FALSE) {
    $csvData[] = array_combine($keys, $row);
}

使用excel（cv）标头格式化JSON输出

1 个答案: