我想读取不断更新的日志文件。如果我有特定的模式,那么我应该能够发送能够执行的邮件。
use strict;
use warnings;
my $line;
my $to = 'abc@abc.com';
my $from = 'xyz@abc.com';
my $subject = 'Connection Pool Issue';
my $message = 'There is connection pool issue. Please check Logs for more details';
open my $fh, '<', 'error.txt';
my @file = <$fh>;
close $fh;
foreach my $line (@file) {
if ($line =~ /The connection is closed./)
{
open(MAIL, "|/usr/sbin/sendmail -t");
print MAIL "To: $to\n";
print MAIL "From: $from\n";
print MAIL "Subject: $subject\n\n";
# Email Body
print MAIL $message;
close(MAIL);
print "Email Sent Successfully\n";
last;
}
}
我不想从文件处理程序0中读取文件,这意味着从起始位置开始。
我希望从当前文件处理程序位置读取文件。 它不应包含已读的行。
请提出建议。 谢谢
答案 0 :(得分:1)
使用File::Tail。
use File::Tail qw( );
my $tail = File::Tail->new( name => $qfn );
while (defined( my $line = $tail->read() )) {
if ($line =~ /The connection is closed\./) {
...
}
}
如果需要以上几行,
use File::Tail qw( );
my $tail = File::Tail->new( name => $qfn );
my @buf;
while (defined( my $line = $tail->read() )) {
push @buf, $line;
if ($line =~ /The connection is closed\./) {
...
@buf = ();
}
}
答案 1 :(得分:0)
我已经用两种方法解决了这个问题。
没有模块,您可以执行以下操作:
-Check if line count file exists and read into variable
-loop through file line by line, increment counter
-if $loop_line_count < $line_count_previous_run : skip
-if $total_line_count < $line_count_previous_run : reset file count to 0
-write total_line_count to file
带有File :: Tail
my $file=File::Tail->new( name=>"$log_file",internal=>10, maxinterval=>30, adjustafter=>5);
while (defined(my $line=$file->read)) {
...
}