Question

我是JavaScript新手，我有一个问题。我想通过检查从数据库中删除数据。通过我的代码，我设法擦除了我的数据，但是检查不起作用。

我第一次在函数msg（）中返回的值为true，但似乎不起作用，所以我添加了

window.location = "delete.php?"

但这不能解决我的问题。谁能展示如何解决这个问题？

我的php代码（delete.php）在这里：

<?php
$con = mysqli_connect("localhost", "root", "", "mybase");
if(isset($_GET["btn"])){
 $sql = 'DELETE FROM user;';
 if(mysqli_query($con, $sql)==1){
    //echo "Records added successfully.";
 } else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($conn);
    }
}
?>

我的html代码在这里：

<form action="delete.php" method="get">
<input type="submit" value="Delete your base" onclick="msg()" name="btn">
</form>
</div>
</body>
</html>
<script>
function msg(){
    var my = confirm("Are you sure you want to delete?");
    if (my) {
           //return true;
       window.location = "delete.php?"
         }
 }
</script>

Answer 1

在msg（）中设置要删除的ID。

type Node<T> = {
    type: 'node',
    node: Array<Filter<T>>;
}
type Method<T> = {
    type: 'method',
    method: Condition<T>;
}
type NodeOrMethod<T> = Node<T> | Method<T>;

cost a: NodeOrMethod<T> = { // valid
  type: 'node',
  node: [...]
}

cost b: NodeOrMethod<T> = { // valid
  type: 'method',
  method: ...
}

cost c: NodeOrMethod<T> = { // type error
  type: 'method',
  node: [...],
  method: ...
}

Delete.php

<form action="delete.php" method="get">
<input type="submit" value="Delete your base" onclick="msg(<?php echo $id; ?>)" name="btn">
</form>
</div>
</body>
</html>
<script>
function msg(id){
    var my = confirm("Are you sure you want to delete?");
    if (my) {
           //return true;
       window.location = "delete.php?deleteid="+id;
         }
 }
</script>

通过检查从数据库中删除我的数据

1 个答案: