Question

我想抓取一个网页，并仅返回GTM容器ID（在下面的示例中为GTM-5LS3NZ）。该代码不应查找确切的容器ID，而应查找模式，因为我将在多个站点上使用它。

到目前为止，我可以搜索标题并打印包含GTM的整个文本，但是我不知道如何将搜索结果和正则表达式一起格式化以仅返回GTM-5LS3NZ（在此示例中）。

import urllib3
import re
from bs4 import BeautifulSoup

http = urllib3.PoolManager()

response = http.request('GET', "https://www.observepoint.com/")
soup = BeautifulSoup(response.data,"html.parser")

GTM = soup.head.findAll(text=re.compile(r'GTM'))
print(GTM)

注意：GTM ID可以包含6或7个字母数字字符，因此我希望容器ID的正则表达式类似于^ GTM- [A-Z0-9]-我不知道如何指定6或7个字符。

澄清我的追求。如果运行上面的代码，则会得到以下内容。

["(function (w, d, s, l, i) {\n      w[l] = w[l] || [];\n      w[l].push({\n        'gtm.start': new Date().getTime(),\n        event: 'gtm.js'\n      });\n      var f = d.getElementsByTagName(s)[0],\n        j = d.createElement(s),\n        dl = l != 'dataLayer' ? '&l=' + l : '';\n      j.async = true;\n      j.src =\n        'https://www.googletagmanager.com/gtm.js?id=' + i + dl;\n      f.parentNode.insertBefore(j, f);\n    })(window, document, 'script', 'dataLayer', 'GTM-5LS3NZ');"]

我要的是GTM-5LS3NZ。

Answer 1

由于评论中的帮助，我现在已经解决了。这就是我的追求：

import re
from bs4 import BeautifulSoup

http = urllib3.PoolManager()

response = http.request('GET', "https://www.observepoint.com/")
soup = BeautifulSoup(response.data,"html.parser")

GTM = soup.head.findAll(text=re.compile(r'GTM'))
print(re.search("GTM-[A-Z0-9]{6,7}",str(GTM))[0])

Answer 2

几天前我做了类似的事情，然后快速重写就给了我

import urllib3
import re
from bs4 import BeautifulSoup

http = urllib3.PoolManager()

response = http.request('GET', "https://www.observepoint.com/")
soup = BeautifulSoup(response.data,"html.parser")

pattern  =re.compile(r'GTM-([a-zA-Z0-9]{6,7})')
found = soup.head.find(text=pattern)
if found:
    match = pattern.search(found)
    if match:
        print(match.group(1))

这给了我GTM-5LS3NZ作为输出。

Answer 3

您还可以从适当的评论中提取

import requests
from bs4 import BeautifulSoup, Comment

r = requests.get('https://www.observepoint.com/')
soup = BeautifulSoup(r.content, 'lxml')
for comment in soup.findAll(text=lambda text:isinstance(text, Comment)):
    if 'iframe' in comment:
        soup = BeautifulSoup(comment, 'lxml')
        id = soup.select_one('iframe')['src'].split('=')[1]
        print(id)
        break

从网站上用美丽的汤刮擦文本字符串

3 个答案: