我正在尝试使用玩笑为redux异步动作创建者编写单元测试。
asyncActions.js:
const startSignInRequest = () => ({
type: START_SIGNIN_REQUEST
});
// action creator to dispatch the success of sign In
export const signInSucceded = user => ({
type: SIGNIN_USER_SUCCEEDED,
user
});
// action creator to dispatch the failure of the signIn request
export const signInFailed = error => ({
type: SIGNIN_USER_FAILED,
error
});
const signInUser = user => dispatch => {
dispatch(startSignInRequest);
return signInApi(user).then(
response => {
const { username, token } = response.data;
dispatch(signInSucceded(username));
localStorage.setItem("token", token);
history.push("/homepage");
},
error => {
let errorMessage = "Internal Server Error";
if (error.response) {
errorMessage = error.response.data;
}
dispatch(signInFailed(errorMessage));
dispatch(errorAlert(errorMessage));
}
);
};
signInApi.js:
import axios from "axios";
import { url } from "../../env/config";
const signInApi = async user => {
const fetchedUser = await axios.post(`${url}/signIn`, {
email: user.email,
password: user.password
});
return fetchedUser;
};
在redux官方文档的Writing tests中,他们使用fetch-mock
库。但是,我认为该库称为真正的Api。
我尝试使用jest mocks
模拟axios api。
/ __ mocks / signInApi.js:
const users = [
{
login: 'user 1',
password: 'password'
}
];
export default function signInApi(user) {
return new Promise((resolve, reject) => {
const userFound = users.find(u => u.login === user.login);
process.nextTick(() =>
userFound
? resolve(userFound)
// eslint-disable-next-line prefer-promise-reject-errors
: reject({
error: 'Invalid user credentials',
}),
);
});
}
__ tests / asyncActions.js:
jest.mock('../axiosApis/signInApi');
import * as actions from '../actions/asyncActions';
describe('Async action creators', async () => {
it('Should create SIGN_IN_USER_SUCCEEDED when signIn user has been done', () => {
const user = {
login: 'user 1',
password: 'password'
}
await expect(actions.signInUser(user)).resolves.toEqual({
user
})
})
});
测试失败,我得到了:
expect(received).resolves.toEqual()
Matcher error: received value must be a promise
Received has type: function
Received has value: [Function anonymous]
我怎么只能用玩笑来嘲笑这个异步动作创建者?
答案 0 :(得分:0)
编辑:我必须编辑我的答案,因为第一个答案指向错误的方向。
因此,根据我的理解,您想模拟Action + Return值。在您的情况下,我将立即返回您的模拟函数的结果。因为您没有嘲笑axios.post
,所以不需要将所有内容包装在promise中并返回它。您不仅在嘲笑HTTP调用,还在嘲笑整个操作。
const users = [
{
login: 'user 1',
password: 'password'
}
];
export default function signInApi(user) {
const userFound = users.find(u => u.login === user.login);
return (userFound ? userFound : {
error: 'Invalid user'
});
}
答案 1 :(得分:0)
看起来您需要更新您的模拟才能解析为这样的对象:
export default function signInApi(user) {
return new Promise((resolve, reject) => {
const userFound = users.find(u => u.login === user.login);
process.nextTick(() =>
userFound
? resolve({ // <= resolve to an object
data: {
username: 'the username',
token: 'the token'
}
})
// eslint-disable-next-line prefer-promise-reject-errors
: reject({
error: 'Invalid user credentials',
}),
);
});
}
...然后您真正要测试的是actions.signInUser
返回一个函数,可以使用user
...
...然后返回另一个函数,可以使用dispatch
来调用该函数,以调度适当的操作:
jest.mock('./signInApi');
import * as actions from './asyncActions';
describe('Async action creators', () => {
it('Should create SIGN_IN_USER_SUCCEEDED when signIn user has been done', async () => {
const user = {
login: 'user 1',
password: 'password'
};
const dispatch = jest.fn();
await actions.signInUser(user)(dispatch); // <= call the function on a user, then call the resulting function on a dispatch
expect(dispatch).toHaveBeenCalledTimes(2); // Success!
expect(dispatch).toHaveBeenNthCalledWith(1, { type: START_SIGNIN_REQUEST }); // Success!
expect(dispatch).toHaveBeenNthCalledWith(2, { type: SIGNIN_USER_SUCCEEDED, user: 'the username' }); // Success!
})
});