如何使用python使用训练数据集预测测试数据集

时间:2019-04-23 13:41:27

标签: python

我一直在用python进行情感分析,以进行机器学习模型比较。我有一个训练数据集,分别带有手动标记的-1、0、1代表消极,中立和积极的情绪。并且一直在使用train_test_split将我的训练数据集拆分为一个测试和训练数据集。我只是想知道如何使用训练数据来预测单独的测试数据集?我在网上找到的所有内容都使用sklearn train_test_split。

import pandas as pd
df = pd.read_csv('Consumer_Complaints.csv')
df.head()


df = df[pd.notnull(df['Text'])]
col = ['Sentiment', 'Text']
df = df[col]

df.columns = ['Sentiment', 'Text']
df['category_id'] = df['Sentiment'].factorize()[0]
from io import StringIO
category_id_df = df[['Sentiment',   'category_id']].drop_duplicates().sort_values('category_id')
category_to_id = dict(category_id_df.values)
id_to_category = dict(category_id_df[['category_id', 'Sentiment']].values)

import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8,6))
df.groupby('Sentiment').Text.count().plot.bar(ylim=0)
plt.show()

from sklearn.feature_extraction.text import TfidfVectorizer

tfidf = TfidfVectorizer(sublinear_tf=True, min_df=5, norm='l2', encoding='latin-1', ngram_range=(1, 2), stop_words='english')

features = tfidf.fit_transform(df.Text).toarray()
labels = df.category_id
features.shape

from sklearn.feature_selection import chi2
import numpy as np

N = 2
for Sentiment, category_id in sorted(category_to_id.items()):
  features_chi2 = chi2(features, labels == category_id)
  indices = np.argsort(features_chi2[0])
  feature_names = np.array(tfidf.get_feature_names())[indices]
  unigrams = [v for v in feature_names if len(v.split(' ')) == 1]
  bigrams = [v for v in feature_names if len(v.split(' ')) == 2]
  print("# '{}':".format(Sentiment))
  print("  . Most correlated unigrams:\n       . {}".format('\n       . '.join(unigrams[-N:])))
  print("  . Most correlated bigrams:\n       . {}".format('\n       . '.join(bigrams[-N:])))

from sklearn.model_selection import train_test_split
from sklearn.feature_extraction.text import CountVectorizer
from sklearn.feature_extraction.text import TfidfTransformer
from sklearn.naive_bayes import MultinomialNB

X_train, X_test, y_train, y_test = train_test_split(df['Text'], df['Sentiment'], random_state = 0)
count_vect = CountVectorizer()
X_train_counts = count_vect.fit_transform(X_train)
tfidf_transformer = TfidfTransformer()
X_train_tfidf = tfidf_transformer.fit_transform(X_train_counts)


from sklearn.linear_model import LogisticRegression
from sklearn.ensemble import RandomForestClassifier
from sklearn.naive_bayes import MultinomialNB
from sklearn.svm import LinearSVC

from sklearn.model_selection import cross_val_score


models = [
    RandomForestClassifier(n_estimators=200, max_depth=3, random_state=0),
    LinearSVC(),
    MultinomialNB(),
    LogisticRegression(random_state=0),
]


CV = 5
cv_df = pd.DataFrame(index=range(CV * len(models)))
entries = []
for model in models:
  model_name = model.__class__.__name__
  accuracies = cross_val_score(model, features, labels, scoring='accuracy', cv=CV)
  for fold_idx, accuracy in enumerate(accuracies):
    entries.append((model_name, fold_idx, accuracy))
cv_df = pd.DataFrame(entries, columns=['model_name', 'fold_idx',  'accuracy'])

import seaborn as sns

sns.boxplot(x='model_name', y='accuracy', data=cv_df)
sns.stripplot(x='model_name', y='accuracy', data=cv_df, 
          size=8, jitter=True, edgecolor="gray", linewidth=2)
plt.show()

cv_df.groupby('model_name').accuracy.mean()

from sklearn.model_selection import train_test_split

model = LinearSVC()

X_train, X_test, y_train, y_test, indices_train, indices_test =    train_test_split(features, labels, df.index, test_size=0.33, random_state=0)
model.fit(X_train, y_train)
y_pred = model.predict(X_test)


from sklearn.metrics import confusion_matrix

conf_mat = confusion_matrix(y_test, y_pred)
fig, ax = plt.subplots(figsize=(8,6))
sns.heatmap(conf_mat, annot=True, fmt='d',   xticklabels=category_id_df.Sentiment.values,      yticklabels=category_id_df.Sentiment.values)
plt.ylabel('Actual')
plt.xlabel('Predicted')
plt.show()

from sklearn import metrics
print(metrics.classification_report(y_test, y_pred,                                         target_names=df['Sentiment'].unique()))

1 个答案:

答案 0 :(得分:-1)

我认为您可以将所需的任何内容分配给变量X_test和y_test。使用一个数据集并将其拆分只是实现该目标的一种方法-并且是一种确保数据集属于同一总体的方法。

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