我有一个表my_table
,其中的jsonb列包含一些数据,例如,在单行中,该列可以包含以下数据:
[
{
"x_id": "1",
"type": "t1",
"parts": [
{ "part_id": "1", price: 400 },
{ "part_id": "2", price: 500 },
{ "part_id": "3", price: 0 }
]
},
{
"x_id": "2",
"type": "t1",
"parts": [
{ "part_id": "1", price: 1000 },
{ "part_id": "3", price: 60 }
]
},
{
"x_id": "3",
"type": "t2",
"parts": [
{ "part_id": "1", price: 100 },
{ "part_id": "3", price: 780 },
{ "part_id": "2", price: 990 }
]
}
]
我需要帮助,找到如何在给定parts
和x_id
的情况下从part_id
数组中删除元素。
示例
鉴于x_id=2
和part_id=1
,我需要将数据更新为:
[
{
"x_id": "1",
"type": "t1",
"parts": [
{ "part_id": "1", price: 400 },
{ "part_id": "2", price: 500 },
{ "part_id": "3", price: 0 }
]
},
{
"x_id": "2",
"type": "t1",
"parts": [
{ "part_id": "3", price: 60 }
]
},
{
"x_id": "3",
"type": "t2",
"parts": [
{ "part_id": "1", price: 100 },
{ "part_id": "3", price: 780 },
{ "part_id": "2", price: 990 }
]
}
]
PS1:无法对这些数据进行标准化,因此这不是可行的解决方案。
PS2:我正在运行PostgreSQL 9.6
PS3:我已经检查了this question和this question,但是与其他问题相比,我的数据结构似乎过于复杂,因此无法应用给出的答案。
Edit1 :json数据可能很大,尤其是parts
数组,该数组可以从少至0个元素到数千个元素。
答案 0 :(得分:0)
这应该有效,只需要另一个唯一列(通常是主键)
创建测试表
create table test_tab(
id serial primary key,
j jsonb
);
insert into test_tab
(j)
values
('[
{
"x_id": "1",
"type": "t1",
"parts": [
{ "part_id": "1", "price": 400 },
{ "part_id": "2", "price": 500 },
{ "part_id": "3", "price": 0 }
]
},
{
"x_id": "2",
"type": "t1",
"parts": [
{ "part_id": "1", "price": 1000 },
{ "part_id": "3", "price": 60 }
]
},
{
"x_id": "3",
"type": "t2",
"parts": [
{ "part_id": "1", "price": 100 },
{ "part_id": "3", "price": 780 },
{ "part_id": "2", "price": 990 }
]
}
]');
然后拆分json,过滤不必要的数据,然后再次重新创建json:
select id, jsonb_agg( jsonb_build_object('x_id',xid, 'type',type, 'parts', case when inner_arr = '[null]'::jsonb then parts_arr::jsonb else inner_arr end) )
from (
select
id,
value->>'x_id' as xid,
jsonb_agg(inner_arr) as inner_arr,
max(value->>'parts') as parts_arr,
max(value->>'type') as type
from (
select * ,
case when value->>'x_id'='2' then jsonb_array_elements(value->'parts') else NULL end inner_arr
from test_tab
join lateral jsonb_array_elements(j)
on true
) t
where
inner_arr->>'part_id' is distinct from '1'
group by id, value->>'x_id'
) t
group by id
答案 1 :(得分:0)
我认为您可以使用#-
运算符(请参阅functions-json
),您只需要找到从以下位置删除数组元素的路径即可。
select
data #- p.path
from test as t
cross join lateral (
select array[(a.i-1)::text,'parts',(b.i-1)::text]
from jsonb_array_elements(t.data) with ordinality as a(data,i),
jsonb_array_elements(a.data->'parts') with ordinality as b(data,i)
where
a.data ->> 'x_id' = '2' and
b.data ->> 'part_id' = '1'
) as p(path)
或
update test as t set
data = data #- (
select
array[(a.i-1)::text,'parts',(b.i-1)::text]
from jsonb_array_elements(t.data) with ordinality as a(data,i),
jsonb_array_elements(a.data->'parts') with ordinality as b(data,i)
where
a.data ->> 'x_id' = '2' and
b.data ->> 'part_id' = '1'
)
更新好吧,如果数据中不存在给定路径,则有一个合理的注释,即更新部分无法正常工作。我猜在这种情况下,您将在where子句中重复表达式:
update test as t set
data = data #- (
select
array[(a.i-1)::text,'parts',(b.i-1)::text]
from jsonb_array_elements(t.data) with ordinality as a(data,i),
jsonb_array_elements(a.data->'parts') with ordinality as b(data,i)
where
a.data ->> 'x_id' = '2' and
b.data ->> 'part_id' = '23222'
)
where
exists (
select *
from jsonb_array_elements(t.data) as a(data),
jsonb_array_elements(a.data->'parts') as b(data)
where
a.data ->> 'x_id' = '2' and
b.data ->> 'part_id' = '23222'
)
或者您可以使用自我加入:
update test as t2 set
data = t.data #- p.path
from test as t
cross join lateral (
select array[(a.i-1)::text,'parts',(b.i-1)::text]
from jsonb_array_elements(t.data) with ordinality as a(data,i),
jsonb_array_elements(a.data->'parts') with ordinality as b(data,i)
where
a.data ->> 'x_id' = '2' and
b.data ->> 'part_id' = '23232'
) as p(path)
where
t.ctid = t2.ctid