我想在输入数据后将datagridview转换为ini文件

时间:2019-04-23 06:02:30

标签: winforms ini

输入数据后,我想将datagridview转换为ini文件。

http://www.hoons.net/Board/qacshap/Content/67073

当我在上方输入网址时,

我尝试将数据放入网格中,然后按导出按钮以节,键,值的形式将其另存为.ini文件。我该怎么办?在代码内部,内容创建为ini文件,而不是网格。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Runtime.InteropServices;
using System.IO;

namespace EXPORT
{
    public partial class Form1 : DevExpress.XtraEditors.XtraForm
    {
        [DllImport('kernel32')]

        public static extern long WritePrivateProfileString(string section, string key, string val, string filePath);

        [DllImport('kernel32')]

        public static extern int GetPrivateProfileString(string section, string key, string def, StringBuilder retVal, int size, string filePath);
        static string path = 'C:\\Test.ini';
        public Form1()
        {
            InitializeComponent();
            dataGridView1.AllowUserToAddRows =true; //자동 행 추가
            dataGridView1.AutoGenerateColumns = false;
        }

        private void button1_Click(object sender, EventArgs e)
        {
            WritePrivateProfileString('SECTION', 'KEY', 'VALUE', @'C:\ConnectionInfo.ini');
            MessageBox.Show('EXPORT successfully to *.INI format');


        }
        private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
        {


        }
        private void WriteInFile(string section,string key,string value,string path)
        {
            WritePrivateProfileString(section, key, value, path);
            if (value == null)
            {
                throw new ArgumentException();
            }
        }

        private void button2_Click(object sender, EventArgs e)  //ADD_ROW Button
        {
            DataGridViewButtonColumn button = new DataGridViewButtonColumn();
            {
                dataGridView1.Rows.Add();
            }
        }
    }
}

1 个答案:

答案 0 :(得分:0)

您可以使用我的MadMilkman.Ini库,方法如下:

private void button1_Click(object sender, EventArgs e)
{
    IniFile iniFile = new IniFile();
    IniSection iniSection = null;

    foreach (DataGridViewRow row in this.dataGridView1.Rows)
    {
        if (row.IsNewRow)
            break;

        string section = row.Cells[0].Value?.ToString();
        string key = row.Cells[1].Value.ToString();
        string value = row.Cells[2].Value.ToString();

        if (!string.IsNullOrEmpty(section))
            iniSection = iniFile.Sections.Add(section);

        iniSection.Keys.Add(key, value);
    }

    iniFile.Save("C:\\Test.ini");
}

此外,这是生成的“ Test.ini”文件的样子:

[a]
123=456
789=234
345=678
[b]
123=456
789=234
345=678