Question

这是我的代码：该错误表明我的int(user month) -1必须是字符串或数字。但是我很困惑，因为我在列表[0]中有电话号码

def change_date_format(user_date):
    user_date_values = user_date.split("/")

    user_month = user_date_values[0]
    user_day = user_date_values[1]
    user_year = user_date_values[2]

    return user_date_values, user_day, user_year
def main():
    user_date = input("Enter a date in the form mm/dd/yyyy: ")

    months = ["January", "Febuary", "March", \
              "April", "May", "June",\
              "July", "August", "September", \
              "October", "November", "December"]
    user_month, user_day, user_year = change_date_format(user_date)

    user_month_index = int(user_month) - 1
    user_month_name = months[user_month_index]

    new_date_format = user_month_name + " " + user_day + ", " + \
                      user_year

    print("You typed " + user_date, "The format of your date was changed \
to " + new_date_format, sep = "\n")

main()

Answer 1

您需要在函数user_month中返回change_date_format，而不是列表中的user_date_values

def change_date_format(user_date):
    user_date_values = user_date.split("/")

    user_month = user_date_values[0]
    user_day = user_date_values[1]
    user_year = user_date_values[2]

    return user_month, user_day, user_year

您的预期输出将是。

Enter a date in the form mm/dd/yyyy: 02/02/2002
You typed 02/02/2002
The format of your date was changed to Febuary 02, 2002

您还可以如下所示返回列表本身，变量将得到相应分配。

def change_date_format(user_date):
    user_date_values = user_date.split("/")
    return user_date_values

上面的格式将产生相同的结果，因为列表中的元素将被分配给下面的变量

user_month, user_day, user_year = change_date_format(user_date)

Answer 2

在函数change_date_format中，您将返回列表中的user_month，而不是返回user_date_values。

尝试一下：

def change_date_format(user_date):
    user_date_values = user_date.split("/")

    user_month = user_date_values[0]
    user_day = user_date_values[1]
    user_year = user_date_values[2]

    return user_month, user_day, user_year

TypeError：int（）参数必须是字符串，类似字节的对象或数字，而不是“列表”？

2 个答案: