Question

我有某些动态数据，其中包含.jpg，.png等文件格式，除此之外，还有.zip，.rar等其他格式，因此在这里我如何过滤和仅获取.jpg，结果。 png并忽略zip和rar的结果？

例如“数据”：“ 123.jpg”

  Results = {
    "data": [
      {
        "_score": 0.36464313,
        "_type": "data",
        "_id": "abcd",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcd",
            "creation_utctime": "1477335693653",
            "data":"123.jpg"
          },
          "enduser": "free"
        },
        "_index": "dell_laptop"
      },
      {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcde",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"123.png"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      },
      {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcdef",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"123.rar"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      },
       {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcdef",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"1235.zip"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      }
    ],

  }

通常我使用这种逻辑来获取嵌套值：

    this.rows=[];

    for (var res in this.Result) {
      var row = {};
      for (var key in this.Result[res]['_source']) {
        if (typeof this.Result[res]['_source'][key] === 'object') {
          for (var k in this.Result[res]['_source'][key]) {
            let temp = key + "." + k;
            row[temp] = this.Result[res]['_source'][key][k];
          }
        } else {
          row[key] = this.Result[res]['_source'][key]
        }
        row['_id'] = this.Result[res]['_id'];
      }
      this.rows.push(row);
    }

Answer 1

您可以将Array.prototype.filter()与String.prototype.match()一起使用正则表达式。

let data= [
      {
        "_score": 0.36464313,
        "_type": "data",
        "_id": "abcd",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcd",
            "creation_utctime": "1477335693653",
            "data":"123.jpg"
          },
          "enduser": "free"
        },
        "_index": "dell_laptop"
      },
      {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcde",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"123.png"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      },
      {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcdef",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"123.rar"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      },
       {
        "_score": 0.36464314,
        "_type": "data",
        "_id": "abcdef",
        "_source": {
          "filter": "data",
          "information": {
            "product_id": "abcde",
            "creation_utctime": "1477335693653",
            "data":"1235.zip"
          },
          "enduser": "free"
        },
        "_index": "lenovo_laptop"
      }
    ]

  let result=data.filter(a=>a._source.information.data.match(/(\.|\/)(gif|jpe?g|png)$/i))
  console.log(result)
  // if you want to ignore some files do this
   let ignoredresult=data.filter(a=>!a._source.information.data.match(/(\.|\/)(gif|jpe?g|png)$/i))
   console.log("--------------------")
   console.log(ignoredresult)

如何在一定条件下从动态数据中过滤结果

1 个答案: