Question

我很难为此问题创建循环。

计算所得税要求应用程序将所有先前税收范围内的所有税收累加到收入的括号，如下表所示。 a）此外，您必须使用循环来解决此问题。

这是我到目前为止所拥有的

        int[] upper = { 9525, 38700, 82500, 157500, 200000, 500000, };
        int[] rate = { 10, 12, 22, 24, 32, 35, 37 };
        double tax;
        Write("Please enter your income >> ");
        double income = Convert.ToInt32(ReadLine());

        for (int i = 0; i < upper.Length; i++)
        {
            if (income <= upper[i])
            {
                tax = income * rate[i];

            }

        }

如果收入为100,000美元，则循环逻辑应该像这样

IncomeTax = 
  ($ 9,525[upper[0]]) * 10%[rate[0]] 
+ ($38,700[upper[1]] - $9,525[upper[0]]) * 12%[rate[1]] 
+ ($82,500[upper[2]] - $38,700[upper[1]]) * 22%[rate[2]] 
+ ($100,000[income] - $82,500[upper[2]]) * 24%[rate[3]] = $18,289.50[total]

任何帮助将不胜感激！

Answer 1

这个小代码有太多问题。

您要重写“税”，而您想对所有税的价值求和以得出一种合计税
您的条件income <= upper[i]在此情况下不适合计算税金
您不是在增量(upper[i] - upper[i -1])上征税，而仅在upper[i]上征税
您计算税款的公式是错误的。
一旦发现自己的收入少于平板（上[i]），就应该打破循环

但是至少我可以看到您的努力，因此我发布了一个有效的代码供您参考（您可以进一步改进它）

        //added , 9999999999 to make the last slab (37%) tends to infinite 
        long[] upper = { 9525, 38700, 82500, 157500, 200000, 500000, 9999999999 };
        int[] rate = { 10, 12, 22, 24, 32, 35, 37 };
        double tax = 0.0;
        Console.WriteLine("Please enter your income >> ");
        //if income is of double data type, we should convert console into double instead of int
        double income = Convert.ToDouble(Console.ReadLine());
        double taxCalculatedAmount = 0.0;

        for (int i = 0; i < upper.Length; i++)
        {
            //Note: here I am calculating the delta 
            //which I will use to calculate the tax for the slab.
            double incomeToCalculateTax  =
                upper[i] <= income ? (i == 0 ? upper[i] : upper[i] - upper[i - 1]) : 
                                     (i == 0 ? income : income - upper[i - 1]);

            //Condition which will check if amount on which we have calculated tax is exceeding total amount
            if (income > taxCalculatedAmount)
            {
                //proper formula of calculating tax
                tax += (incomeToCalculateTax * rate[i]) / 100;
                taxCalculatedAmount += incomeToCalculateTax;
            }
            else
                break;
        }

Answer 2

以下是计算所需结果的自包含静态函数。尽管对于练习来说可能没有什么区别，但通常建议不要使用浮点数进行货币计算，因为在进行大量处理时可能会失去精度；要么转换为最低的单位（美分或其他），然后使用整数（或多头），或者使用小数，如下所示。

public static decimal IncomeTax(decimal income)
{
    // Only positive income can be taxed
    if (income <= 0M) return 0M;

    // Initialize bracket limits and rate percentages
    int[] brackets = { 0, 9525, 38700, 82500, 157500,
                       200000, 500000, int.MaxValue };
    int[] rates = { 10, 12, 22, 24, 32, 35, 37 };

    // Start with zero tax
    decimal tax = 0M;

    // Loop over tax rates and corresponding brackets
    for (int i = 0; i < rates.Length; i++)
    {
        // Calculate amount of current bracket
        int currBracket = brackets[i + 1] - brackets[i];

        // If income is below lower bound, exit loop
        if (income < brackets[i]) break;

        // If income is between lower and upper bound,
        if (income < brackets[i + 1])
        {
            // adjust bracket length accordingly
            currBracket = income - brackets[i];
        }

        // Add tax for current bracket to accumulated tax
        tax += (rates[i] / 100M) * currBracket;
    }

    // Return result
    return tax;
}

我需要帮助来解决这个问题

2 个答案: