Question

我想提取第二个_字符之后的字符串，还要删除Microsoft SQL Server查询中的(C)。

字段名称为资产代码

表名是dbo.DynamicsMOJ数据

数据示例：

资产代码的值

CP04K_54560_633331 (C)
CP04K_54560_641121 (C)
ME030_72159_690940 (C)
HB21M_60966_1181492 (C)
AW000_1144713 (C)

以此类推，该字段中的所有值都具有相似的格式，但是有些值只有一个“ _”

我需要获得

'633331'
'641121'
'690940'
'1181492'
'1144713'

Answer 1

我的变体：

SELECT
  txt,
  CHARINDEX('_',REVERSE(txt)), -- there is 0 for four last examples
  --REPLACE(RIGHT(txt,ISNULL(NULLIF(CHARINDEX('_',REVERSE(txt))-1,-1),LEN(txt))),' (C)','')
  -- the next variants is better if we have different count of spaces before '(C)'
  RTRIM(REPLACE(RIGHT(txt,ISNULL(NULLIF(CHARINDEX('_',REVERSE(txt))-1,-1),LEN(txt))),'(C)','')),
  RTRIM(REPLACE(IIF(CHARINDEX('_',txt)=0,txt,RIGHT(txt,CHARINDEX('_',REVERSE(txt))-1)),'(C)',''))
FROM
  (VALUES
    ('CP04K_54560_633331 (C)'),
    ('CP04K_54560_641121 (C)'),
    ('ME030_72159_690940 (C)'),
    ('HB21M_60966_1181492 (C)'),
    ('AW000_1144713 (C)'),
    (NULL),
    (''),
    ('1234567(C)'),
    ('1234567       (C)'),
    ('1234567')
  ) v(txt)

您可以使用以下查询检查数据：

SELECT *
FROM
  (VALUES
    ('CP04K_54560_633331 (C)'),
    ('CP04K_54560_641121 (C)'),
    ('ME030_72159_690940 (C)'),
    ('HB21M_60966_1181492 (C)'),
    ('AW000_1144713 (C)'),
    (NULL),
    (''),
    ('1234567(C)'),
    ('1234567       (C)'),
    ('1234567')
  ) v(txt)
WHERE CHARINDEX('_',txt)=0

我认为它将为您提供所有不含'_'的值。

使用分隔符分割字符串

1 个答案: