Question

我正在自学python，并对其他人编写的机器人进行了一些更改。

我正在尝试为NSFW或不适合孩子的单词添加过滤器。我已将这些单词添加到名为config.banned_name_keywords的列表中。

我本来可以通过返回整个tweet来使其正常工作，但我正尝试返回找到的特殊单词，以便对列表进行故障排除和编辑。

我可以使用tweet.text返回整个tweet，但是这将使输出消失并阻塞屏幕。

我也尝试过print（x），但是我不知道在哪里定义。它返回的是首先找到该推文的单词。

for tweet in searched_tweets:
    if any(rtwords in tweet.text.lower().split() for rtwords in config.retweet_tags):
        # The script only cares about contests that require retweeting. It would be very weird to not have to
        # retweet anything; that usually means that there's a link  you gotta open and then fill up a form.
        # This clause checks if the text contains any retweet_tags
        if tweet.retweeted_status is not None:
            # In case it is a retweet, we switch to the original one
            if any(y in tweet.retweeted_status.text.lower().split() for y in config.retweet_tags):
                tweet = tweet.retweeted_status
            else:
                continue
        if tweet.user.screen_name.lower() in config.banned_users or any(x in tweet.user.name.lower() for x in config.banned_name_keywords):
            # If it's the original one, we check if the author is banned
            print("Avoided user with ID: " + tweet.user.screen_name + " & Name: " + tweet.user.name)
            continue
        elif any(z in tweet.text.lower().split() for z in config.banned_name_keywords):
            # If the author isn't banned, we check for words we don't want
            print("Avoided tweet with words:" + z)
            continue

Answer 1

不是现在，但是您将能够通过assignment expressions在Python 3.8中使用：

elif any((caught := z) in tweet.text.lower().split() for z in config.banned_name_keywords):
    print("Avoided tweet with word: " + caught)

如果您想捕获所有可能出现的禁用词，请不要使用any，因为这样做的目的是在找到一个匹配项后立即停止。为此，您只想计算交点（您现在也可以这样做）：

banned = set(config.banned_name_keywords)

...

else:
    caught = banned.intersection(tweet.text.lower().split())
    if caught:
        print("Avoided tweet with banned words: " + caught)

（这本身也可以使用赋值表达式来缩短：

elif (caught := banned.intersection(tweet.text.lower().split())):
    print("Avoided tweet with banned words: " + caught)

）

Answer 2

更改此行

if tweet.user.screen_name.lower() in config.banned_users or any(x in tweet.user.name.lower() for x in config.banned_name_keywords):

到

try:
    # matched_banned_keyword below is the `SPECIFIC` word that matched
    matched_banned_keyword = config.banned_name_keywords[config.banned_name_keywords.index(tweet.user.name.lower())] 
except:
    matched_banned_keyword = None
if tweet.user.screen_name.lower() in config.banned_users or matched_banned_keyword:
    print("Avoided user with ID: " + tweet.user.screen_name + " & Name: " + tweet.user.name)

L.index(x)函数返回列表x中L的索引，如果列表x中不存在L，则会引发异常。您可以捕获在user.screen_name.lower()中不存在config.banned_name_keywords

时发生的异常

我可以返回在任何迭代中找到的值吗？

2 个答案: