Question

我有一个项目集合，用于存储客户ID和包含该ID以及客户名称的客户集合。

我需要返回客户名称而不是项目API端点的ID，为此，我尝试在Mongoose中使用虚拟填充。

我具有以下架构/模型配置...

const customerSchema = new mongoose.Schema({
    "custId": String,
    "custName": String,
    "addr1": String,
    "addr2": String,
    "city": String,
    "county": String,
    "postcode": String,
    "phone": String,
    "email": String
});

customerSchema.virtual('names', {
    ref: 'customers',
    localField: 'custId',
    foreignField: 'custId'
});
const projectSchema = new mongoose.Schema({
    "projId": String,
    "projName": String,
    "custId": String,
    "custName": {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'customers'
    },
    "projDesc": String,
    "projAdd1": String,
    "projAdd2": String,
    "projCity": String,
    "projCounty": String,
    "projPostcode": String,
    "projLat": String,
    "projLng": String,
    "projStartDate": String,
    "projEndDate": String,
    "projStatus": String,
    "projContacts": [
        String
    ]
});

const custModel = mongoose.model("customers", customerSchema);
const projectModel = mongoose.model("projects", projectSchema);

并在我的API端点代码中使用以下查询...

var result = await projectModel.find().populate('names').exec();

API端点返回数据，但不包含custName。

有人可以帮助吗？

谢谢！

注意到我已经将虚拟机提供给客户模型，因此进行了如下更改...

const projectSchema = new mongoose.Schema({
    "projId": String,
    "projName": String,
    "custId": String,
    "custName": {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'customers'
    },
    "projDesc": String,
    "projAdd1": String,
    "projAdd2": String,
    "projCity": String,
    "projCounty": String,
    "projPostcode": String,
    "projLat": String,
    "projLng": String,
    "projStartDate": String,
    "projEndDate": String,
    "projStatus": String,
    "projContacts": [
        String
    ]
});

projectSchema.virtual('names', {
    ref: 'customers',
    localField: 'custId',
    foreignField: 'custId'
});

const customerSchema = new mongoose.Schema({
    "custId": String,
    "custName": String,
    "addr1": String,
    "addr2": String,
    "city": String,
    "county": String,
    "postcode": String,
    "phone": String,
    "email": String
});

const custModel = mongoose.model("customers", customerSchema);
const projectModel = mongoose.model("projects", projectSchema);

Answer 1

默认情况下，不将Mongoose中的虚拟填充添加到输出中。添加了以下内容，它起作用了...

projectSchema.set('toObject', { virtuals: true });
projectSchema.set('toJSON', { virtuals: true });

猫鼬虚拟人口

1 个答案: