Question

我正在尝试在数据库中进行查询，但是laravel变量正在失去其作用域，并且该查询没有给出任何输出..我尝试使用whereRaw但它不起作用

 public function search_user(Request $r)
{
  try
  {


      if(JWTAuth::User()->role != 'Admin')
          return response()->json(['status'=>False,'error'=>'You do not have permission to Create User.Please Contact your admin for access.']);


      $search_type = $r->search_type;//Possible Values , email , userid , username , phone, role
      $search_text = strtolower($r->search_text);


      $limit = $r->limit;
      $offset = $r->offset;
      $role = JWTAuth::User()->role;

      $user = User::where($search_type,'Like','%'.$search_text.'%')->skip($offset)->take($limit)->toSql();
      $count_of_search = count($user);


      if($role == 'Admin')
          return response()->json(['status'=>true,'data'=>$user,'view_user'=>True,'add_user'=>True , 'edit_user'=>True,'delete_user'=>True,'total_users'=>$count_of_search],200);
      elseif($role == 'User')
          return response()->json(['status'=>true,'data'=>$user,'view_user'=>False,'add_user'=>False , 'edit_user'=>False,'delete_user'=>False,'total_users'=>$count_of_search],200);
      elseif($role == 'Developer')
          return response()->json(['status'=>true,'data'=>$user,'view_user'=>True,'add_user'=>False , 'edit_user'=>False,'delete_user'=>False,'total_users'=>$count_of_search],200);
  }


**Query Output**

"select * from `users` where `username` Like ? limit 5 offset 0"

Answer 1

尝试替换以下行：

$user = User::where($search_type,'Like','%'.$search_text.'%')->skip($offset)->take($limit)->toSql();

通过以下行：

$user = User::where($search_type,'Like','%'.$search_text.'%')->skip($offset)->take($limit)->get();

原因：

toSql()方法返回sql查询，但是get()方法实际上执行查询。此外，如果要计算用户数，可以使用count收集方法。如下：

$count_of_search = $user->count()

Laravel变量失去了查询范围

1 个答案: