Question

每当我按下“取消”按钮时，我都希望pyqt应用程序停止。例如，此应用应该是来自两个表的循环功能。我可以设置一个触发器，该触发器将始终会根据按下“取消”按钮来检查其状况（对/错）。但是有什么方法可以设置全局触发器，该触发器将在任何代码位置停止应用程序进程？

import time
import sys
from PyQt5 import QtCore, QtWidgets, QtGui
from PyQt5.QtWidgets import (QApplication, QWidget, QToolTip, QPushButton, QMessageBox, QTreeWidget, QTreeWidgetItem, QProgressBar, QLabel)

class Pio(QWidget):
    def __init__(self):
        super().__init__()

        self.initUI()
    def initUI(self):

        self.launch = False

        self.pbar = QProgressBar(self)
        self.pbar.setGeometry(20,20,400,50)

        self.okButton = QPushButton(self)
        self.okButton.setGeometry(80, 20, 100, 50)
        self.okButton.move(20, 80)
        self.okButton.setText('launch')

        self.cncl = QPushButton(self)
        self.cncl.setGeometry(300, 20, 100, 50)
        self.cncl.move(320, 80)
        self.cncl.setText('cancel')

        self.okButton.clicked.connect(self.start_loop)
        self.cncl.clicked.connect(self.break_loop)
        self.show()

    def start_loop(self):
        if not self.launch:
            self.launch = True
            print ('started!')
            self.loop_numbers()


    def break_loop(self): 
        print ('canceled!')
        if self.launch:
            print ('work in progress....')
            self.launch = False


    def loop_numbers(self):
        print ('running')

        'action #1 that takes a lot of time '
        'action #2 that also takes a lot of time'

        for n in range(101):
            if self.launch:
                self.pbar.setValue(n)
                time.sleep(0.01)
                QtCore.QCoreApplication.processEvents()

        for n in range(11):
            if self.launch:
                self.pbar.setValue(n*10)
                time.sleep(0.05)
                QtCore.QCoreApplication.processEvents()

if __name__ == '__main__':
    app = QApplication(sys.argv)
    ex = Pio()
    sys.exit(app.exec_())

如果我将self.launch移到loop_numbers()的开头并开始循环，它将在整个过程中运行。

Answer 1

当最后一个窗口关闭时，应用程序将自动关闭，因此您可以尝试将QWidget的{{1}}更改为“ QMainWindow”，只需从取消按钮中调用close。

import sys
import time

from PyQt5 import QtCore
from PyQt5.QtWidgets import QApplication, QMainWindow, QPushButton, QProgressBar


class Pio(QMainWindow):
    def __init__(self):
        super().__init__()

        self.initUI()

    def initUI(self):

        self.launch = False

        self.pbar = QProgressBar(self)
        self.pbar.setGeometry(20, 20, 400, 50)

        self.okButton = QPushButton(self)
        self.okButton.setGeometry(80, 20, 100, 50)
        self.okButton.move(20, 80)
        self.okButton.setText('launch')

        self.cncl = QPushButton(self)
        self.cncl.setGeometry(300, 20, 100, 50)
        self.cncl.move(320, 80)
        self.cncl.setText('cancel')

        self.okButton.clicked.connect(self.start_loop)
        self.cncl.clicked.connect(self.break_loop)

    def start_loop(self):
        if not self.launch:
            self.launch = True
            print('started!')
            self.loop_numbers()

    def break_loop(self):
        print('canceled!')
        if self.launch:
            print('work in progress....')
            self.launch = False

        # Close window and exit application
        self.close()

    def loop_numbers(self):
        print('running')
        'action #1 that takes a lot of time '
        'action #2 that also takes a lot of time'

        for n in range(101):
            if self.launch:
                self.pbar.setValue(n)
                time.sleep(0.01)
                QtCore.QCoreApplication.processEvents()

        for n in range(11):
            if self.launch:
                self.pbar.setValue(n * 10)
                time.sleep(0.05)
                QtCore.QCoreApplication.processEvents()


if __name__ == '__main__':
    app = QApplication(sys.argv)
    mainWindow = Pio()
    mainWindow.show()
    sys.exit(app.exec_())

完全停止运行pyqt5应用程序

1 个答案: