Question

我有以列表形式存储的dict值。这就是它的样子：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]

在这里，在键Length中，我有两个值。 first=steven,initial=s 我想拆分这些值并创建两个新字段，并将其以更新的形式存储在字典中。

必需的输出：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p','first':'prince','initial':'p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s','first':'steven','initial':'s'}
]

这是我尝试过的程序：

d = [
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
{'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
]
field_to_split = "Length"
split_using1 = ','
split_using2 = '='
b =[]
for i in d:
    s = i[field_to_split].split(split_using1)
    print(s)
    b.append(s)
    #print(s)
print(b)

我如何做到这一点...

Answer 1

使用简单的迭代。

例如：

d = [
    {'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=prince,initial=p'},
    {'Driveline': 'Rear-wheel drive', 'Hybrid': 'False', 'Classification': 'Automatic,Transmission', 'Number_of_Forward_Gears': 6, 'Fuel_Type': 'Gasoline', 'Length': 'first=steven,initial=s'}
    ]

for i in d:
    for j in i['Length'].split(","):    #Split string by comma
        i.update(dict([j.split("=")]))  #Split string by eq sign and use dict() method to create a dictionary

输出：

[{'Classification': 'Automatic,Transmission',
  'Driveline': 'Rear-wheel drive',
  'Fuel_Type': 'Gasoline',
  'Hybrid': 'False',
  'Length': 'first=prince,initial=p',
  'Number_of_Forward_Gears': 6,
  'first': 'prince',
  'initial': 'p'},
 {'Classification': 'Automatic,Transmission',
  'Driveline': 'Rear-wheel drive',
  'Fuel_Type': 'Gasoline',
  'Hybrid': 'False',
  'Length': 'first=steven,initial=s',
  'Number_of_Forward_Gears': 6,
  'first': 'steven',
  'initial': 's'}]

如何在python字典中拆分值？

1 个答案: