Question

我需要按此顺序的json文件，因为我必须不断更改json值。这是我要生成的示例文件

1.control_file json中的位置名称标签也应以“”，“”格式括起来我需要帮助。

{
 "user": "dex",
 "issue_no": "test_tkt",
 "start_date": "2017-07-01",
 "end_date": "2017-07-01",
 "geo-ids": [627,438,360],
 "location_names": [
    "India.v1.2a_Final",
    "China.v2.3a_setup",
    "Hongkong.4a"
 ]
}

下面是我写的代码。预期的输出

import json
import os


filename = input("Enter the file name: ")
user = input("Enter the user name: ")
ticket = input("Enter the ticket id: ")
start_date = input("Enter the start date: ")
end_date = input("Enter the end date: ")

test_list=[]
input_list=input("enter the exp names: ")
exports = input_list.split(",")
for names in exports:
        demo = test_list.append(names)
        print(demo)


if not os.path.splitext(filename)[1]:
    filename += ".txt"


with open(filename, 'w') as f:
    json.dump({
        "user": user,
        "ticket": ticket,
        "start_date": start_date,
        "end_date" : end_date,
        "location_names" : [demo]
      }, f, indent=4)


print("JSON saved to file {}".format(os.path.abspath(filename)))

我得到的输出

{
    "user": "dex",
    "ticket": "test_tkt",
    "start_date": "2017-07-01",
    "end_date": "2017-07-01",
    "location_names": [
        None
        None
        None
    ]
}

我想要的输出：

{
 "user": "dex",
 "issue_no": "test_tkt",
 "start_date": "2017-07-01",
 "end_date": "2017-07-01",
 "location_names": [
    "India.v1.2a_Final",
    "China.v2.3a_setup",
    "Hongkong.4a"
 ]
}

Answer 1

您正在将test_list.append()的返回值分配给变量demo，但这将始终为None，因为append()不会返回任何内容。

由于test_list包含名称列表，因此应将其用作值并删除demo变量：

with open(filename, 'w') as f:
    json.dump({
        "user": user,
        "ticket": ticket,
        "start_date": start_date,
        "end_date" : end_date,
        "location_names" : test_list  # Use test_list
      }, f, indent=4)

Answer 2

改用它。

with open(filename, 'w') as f:
json.dump({
    "user": user,
    "ticket": ticket,
    "start_date": start_date,
    "end_date" : end_date,
    "location_names" : [item for item in demo]
  }, f, indent=4)

使用用户输入生成自定义json文件

2 个答案: