如何在SQL Server中分割字符串

Question

我正在尝试从model_interested列中拆分值，以便仅从整个数据模型显示中

SELECT SUBSTRING(model_interested, 20, CHARINDEX('model', model_interested)) AS model_interested 
FROM cust

从model_interested列中的图像中，我只希望显示

"model":"A180"
"model":"A200 AMG FL"

我尝试按字符数进行拆分，但我认为这不是正确的方法。

Answer 1

您可以通过SUBSTRING和CHARINDEX使用以下解决方案：

SELECT SUBSTRING(model_interested, CHARINDEX('"model":"', model_interested) + LEN('"model":"'), CHARINDEX('"', model_interested, CHARINDEX('"model":"', model_interested) + LEN('"model":"')) - (CHARINDEX('"model":"', model_interested) + LEN('"model":"')))
FROM table_name

要获取整个属性（具有属性名称和值），可以使用以下解决方案：

SELECT SUBSTRING(model_interested, CHARINDEX('"model":"', model_interested), CHARINDEX('"', model_interested, CHARINDEX('"model":"', model_interested) + LEN('"model":"')) - CHARINDEX('"model":"', model_interested) + 1)
FROM table_name

您还可以使用JSON_VALUE获取期望值，但是必须将数据更改为有效的JSON值：

SELECT JSON_VALUE(REPLACE(REPLACE(model_interested, '{[', '[{'), ']}', '}]'), '$[0].model')
FROM table_name

demo on dbfiddle.uk

Answer 2

如果使用的SQL Server版本早于2016，则您可以将查询编写为：

;with cte as
(
 SELECT   
       Split.a.value('.', 'VARCHAR(100)') AS model_interested  
 FROM  (
         SELECT CAST ('<M>' + REPLACE([model_interested], '.', '</M><M>') + '</M>' AS XML)
                as  model_interested_xml
         FROM  @cust

        ) AS A CROSS APPLY model_interested_xml.nodes ('/M') AS Split(a)  
    )
select model_interested
from cte
where CHARINDEX('model',model_interested) > 0

演示在这里：https://rextester.com/CCW41495