Question

下面我有以下代码和代码测试，由于某种原因，deepEqual返回false并导致测试失败。现在，从阅读有关doco的内容开始，我希望对于如此简单的事情，它会成为事实吗？任何观点将不胜感激。谢谢

// customer.go
type Customer struct {
    customerID int
    domains []string
    names []string
}
func NewCustomer(customerID int, domains []string, names []string) *Customer{
    return &Customer{
        customerID: customerID,
        domains: domains,
        names:names,
    }
}

// customer_test.go
func TestNewCustomer(t *testing.T) {
    expected := &Customer{123,
        []string{},
        []string{},
    }

    got := NewCustomer(123, []string{}, []string{})

    if got.customerID != expected.customerID {
        t.Errorf("Got: %v, expected: %v", got.customerID, expected.customerID)
    }

    if reflect.DeepEqual(got, expected) {
        t.Errorf("Got: %v, expected: %v", got, expected)
    }
}

输出：

Got: &{123 [] []}, expected: &{123 [] []}

Answer 1

reflect.DeepEqual()按预期返回true，这就是调用您的t.Errorf()的原因。

如果不相等，则您希望测试失败。您只需取消条件即可：

if !reflect.DeepEqual(got, expected) {
    t.Errorf("Got: %v, expected: %v", got, expected)
}

Golang：reflect.DeepEqual返回意外的false

1 个答案: