我有一个包含表单元素的HTML页面。表单包含单选类型的输入和最后一个按钮。我希望单击该按钮时,将调用一个javascript方法,该方法获取所选选项的值并重定向到selectedChoice.html页面。
这是我的HTML页面。
<html>
<head>
<script type="application/javascript" src="../js/navigation.js"></script>
</head>
<body>
<div id="chooseBodyPart">
<form>
<div class="question-text">
<p>Which body part is at dis-ease??</p>
</div>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="chest"> Chest <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="head"> Head <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="shoulders"> Shoulders <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="eyes"> Eyes <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="ears"> Ears <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="heart"> Heart <br>
<button onclick="redirectToNextPageBasedOnResponse();">Proceed</button>
</form>
</div>
</body>
</html>
下面是我的js。
function getListOfChoices(form) {
var choices = form.getElementsByTagName("input");
return choices;
}
// list of choices should be passed to this method and name of checked choice should be returned.
// In case no choice is selected the return null
function getNameOfCheckedChoice(choices) {
var selectedChoice = null;
for (var choiceNumber = 0; choiceNumber < choices.length; choiceNumber++) {
if (choices[choiceNumber].checked) {
selectedChoice = choices[choiceNumber].value;
break;
}
}
return selectedChoice;
}
function redirectToNextPageBasedOnResponse() {
var divContainingForm = document.getElementById("chooseBodyPart");
var form = divContainingForm.getElementsByTagName("form")[0];
var choices = getListOfChoices(form);
var selectedChoice = getNameOfCheckedChoice(choices);
window.location.href = "http://" + window.location.host + "/html/" + selectedChoice + ".html";
}
代码的工作完全是我想要的,但是一旦控件从redirectToNextPageBasedOnResponse()返回,URL不会更改为我编写的代码,而是将查询参数插入到现有URL中,其值等于所选选项。
有人可以解释发生了什么吗?
答案 0 :(得分:0)
欢迎堆栈溢出!
请检查
window.location=url
或
history.pushState({}, "title", url);
相反。
答案 1 :(得分:0)
您只缺少一件事。在提交事件上调用preventDefault()
。
您需要通过onclick="redirectToNextPageBasedOnResponse(event);"
进行活动,然后在处理程序中执行event.preventDefault()
。
function getListOfChoices(form) {
var choices = form.getElementsByTagName("input");
return choices;
}
// list of choices should be passed to this method and name of checked choice should be returned.
// In case no choice is selected the return null
function getNameOfCheckedChoice(choices) {
var selectedChoice = null;
for (var choiceNumber = 0; choiceNumber < choices.length; choiceNumber++) {
if (choices[choiceNumber].checked) {
selectedChoice = choices[choiceNumber].value;
break;
}
}
return selectedChoice;
}
function redirectToNextPageBasedOnResponse(event) {
event.preventDefault();
var divContainingForm = document.getElementById("chooseBodyPart");
var form = divContainingForm.getElementsByTagName("form")[0];
var choices = getListOfChoices(form);
var selectedChoice = getNameOfCheckedChoice(choices);
window.location.href = "http://" + window.location.host + "/html/" + selectedChoice + ".html";
}
<div id="chooseBodyPart">
<form>
<div class="question-text">
<p>Which body part is at dis-ease??</p>
</div>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="chest"> Chest <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="head"> Head <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="shoulders"> Shoulders <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="eyes"> Eyes <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="ears"> Ears <br>
<input class="radio-option" type="radio" name="bodyPartAtDisease" value="heart"> Heart <br>
<button onclick="redirectToNextPageBasedOnResponse(event);">Proceed</button>
</form>
</div>
因此,我们阻止了表单提交的默认行为,并为其添加了自定义行为。