Question

尝试反转字符数组：

def reverse(list_of_chars):
    reversed_string = []
    for x in range(len(list_of_chars)-1,0,-1):
        reversed_string.append(list_of_chars[x])

我在做什么错了？

在原处反转字符串：

def reverse(list_of_chars):
    last_index = list_of_chars[len(list_of_chars) - 1]
    first_index = list_of_chars[0]

    while(first_index != last_index):
        first_index = list_of_chars[0]
        list_of_chars.remove(first_index)
        list_of_chars.append(first_index)

    pass

Answer 1

您做错了两件事：

范围不包含最后一个值，因此您的范围将在到达0之前停止。您需要阅读以下内容：

range(len(list_of_chars) -1, -1, -1):

您需要返回列表。

def reverse(list_of_chars):
    reversed_string = []
    for x in range(len(list_of_chars) -1, -1, -1):
        reversed_string.append(list_of_chars[x])
    return reversed_string

print(reverse([1, 2, 3, 4, 5]))
# prints: [5, 4, 3, 2, 1]

您也可以理解地进行此操作，这可能更易于阅读：

def reverse(l):
    return [l[-(index + 1)] for index in range(len(l))]

Answer 2

list_of_chars = ['z','r','x','e','c']

def reverse(list_of_chars):
    reversed_string = []
    for x in range(len(list_of_chars)-1,-1,-1):
        reversed_string.append(list_of_chars[x])
    print(reversed_string)

reverse(list_of_chars)

output: ['c', 'e', 'x', 'r', 'z']

反转python3.6中的字符数组

2 个答案: