Question

如何更改具有以下元素的列表：

package com.MyWebApp.controller.servlet.filters.tracking;

import java.io.IOException;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
//import javax.servlet.annotation.WebFilter;

//@WebFilter("/TrackingFilter")
public class TrackingFilter implements Filter{

    private FilterConfig config = null;

    public void init(FilterConfig config) throws ServletException{
        this.config = config;
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        System.out.println("HELLO WORLD FROM - MYFILTER");

        System.out.println("GOODBYE CRUEL WORLD - EXIT MYFILTER ");
    }

    public void destroy() {}
}

收件人：

    <filter-mapping>
        <filter-name>TrackingFilter</filter-name>
        <!-- <url-pattern>/*</url-pattern> -->
        <url-pattern>/AppointmentApp/*</url-pattern>
    </filter-mapping>

Answer 1

您可以使用此：

>>> [[i for i in days if not isinstance(i, list)]] + [i for i in days if isinstance(i, list)][0]
[['Mon', 'Tues', 'Wed', 'Thur', 'Fri'], 'Sat', 'Sun']
>>>

Answer 2

l = []
temp = []
for i in days:
if isinstance(i, list):
    l.append(temp)
    temp = []
    for j in i:
        l.append(j)
else:
    temp.append(i)
if temp:
     l.append(temp)
print(l)

输出：

[['Mon', 'Tues', 'Wed', 'Thur', 'Fri'], 'Sat', 'Sun']

Answer 3

由于似乎没有任何规则，该怎么做？

>>> days = ['Mon', 'Tues', 'Wed', 'Thur', 'Fri', ['Sat', 'Sun']]
>>> [days[:-1]] + days[-1]
[['Mon', 'Tues', 'Wed', 'Thur', 'Fri'], 'Sat', 'Sun']
>>>

如何将子列表分解为元素

3 个答案: