为什么减少函数的参数

Question

我已经用reduce内置函数编写了这些代码行，但是对于给定的参数它显示了一个错误。

错误：

TypeError跟踪（最近一次通话）  在       4       5 lst = [1,2,3] ----> 6 reduce（d_n，lst）

TypeError：d_n（）接受1个位置参数，但给出了2个

from functools import reduce
def d_n(digit):
    return(digit)

lst = [1,2,3]
reduce(d_n, lst)

Answer 1

<table id="hosts" border="1">
  <tbody>
    <tr>
      <td><input type="checkbox" checked=""></td>
      <td>127.0.0.1</td>
      <td>localhost</td>
    </tr>
    <tr>
      <td><input type="checkbox"></td>
      <td>255.255.255.255</td>
      <td>broadcasthost</td>
    </tr>
  </tbody>
</table>

关键点：具有两个自变量的功能

您的reduce(...) reduce(function, sequence[, initial]) -> value Apply a function of two arguments cumulatively to the items of a sequence, from left to right, so as to reduce the sequence to a single value. For example, reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates ((((1+2)+3)+4)+5). If initial is present, it is placed before the items of the sequence in the calculation, and serves as a default when the sequence is empty. 函数仅接受一个参数，这使其与d_n()不兼容