Question

我是编程的初学者。您能告诉我代码有什么问题吗？该代码未显示回文，尽管该数字是回文。

public static void main(String[] args) {
    // TODO code application logic here
    Scanner in = new Scanner(System.in);
    int a =0;
    int n =in.nextInt();
    while(n >0){
        int temp =n %10;
        a = a*10+temp;
        n = n/10;
    }
    System.out.println(a);
    if( n ==a){
        System.out.println("The number is palindrome");
    }else{
        System.out.println("The number is not palindrome");
    }
}

输出：

16461
16461
The number is not palindrome

Answer 1

您的代码可以正常工作，除了您没有保留原始值以将其与您计算出的反向数字进行比较之外。通过保存原始输入的副本，并在末尾使用它与您的计算结果进行比较，这可以为您的输入值起作用：

public static void main(String[] args) {
    // TODO code application logic here
    Scanner in = new Scanner(System.in);
    int a = 0;
    int n = in.nextInt();
    int orign = n;
    while(n >0){
        int temp = n %10;
        a = a*10+temp;
        n = n/10;
    }
    System.out.println(a);
    if( orign == a){
        System.out.println("The number is palindrome");
    }else{
        System.out.println("The number is not palindrome");
    }
}

示例会话：

16461
16461
The number is palindrome

12345
54321
The number is not palindrome

3
3
The number is palindrome

检测数字回文不正常的功能

1 个答案: