我正在尝试使用PHP通过JSON进行解析,然后打印出父属性的名称,后跟各项。
这是JSON
{
"Specials": [{
"name": "Shirt","dsc":"cotton shirt",
"vari": [{ "name":"red", "price":25.80 },{ "name":"green", "price":26.50 }]
},
{
"name":"shorts","dsc":"one size","price":15.99
},
{
"name":"shoes","dsc":"black shoes",
"vari": [{ "name":"capri", "price":37.80 },{ "name":"shooters", "price":28.50 }]
}],
"Jumpers": [{
"name": "Glax Red","dsc":"thin lightweight","price":22.99
},
{
"name": "Bazoo Care","dsc":"ideal for winter","price":32.99
}]
}
我用下面的方法来遍历它:
$readjson = file_get_contents('products.json') ;
$data = json_decode($readjson);
foreach ($data as $products) {
foreach ($products as $product) {
echo $product->name."<br>".$product->dsc."<br>";
if (isset($product->price))
{
echo " ".$product->price."<br>";
}
else {
foreach ($product->vari as $var) {
echo $var->name." ".$var->price."<br/>";
}
}
输出为:
衬衫 棉衬衫 红色25.8 绿色26.5 短裤 一种尺寸 15.99 ...
我想先打印属性的名称,然后显示其中的项目,它应该像这样:
特价
衬衫 棉衬衫 红色25.8 绿色26.5
短裤 一种尺寸 15.99 ...
跳线
淡红色 轻巧 22.99
Bazoo护理 冬天的理想之选 32.99
我已将其添加为外部嵌套循环:
foreach ($data as $products => $value) {
echo $products;}
但这只会返回第一个对象名称。如何实现以上目标?
这是JSON的可视化。
答案 0 :(得分:0)
将您json
转换为数组并循环遍历
$data = json_decode($readjson, true);
我们在这里传递true
参数,这意味着没有对象的数组。
foreach($data as $key => $value){
foreach($value as $k => $v){
echo '<b>'.$v['name'].'</b> '.' '.$v['dsc'];
echo isset($v['price']) ? $v['price'] : ' ';
if(array_key_exists('vari', $v)){
$vari = array_column($v['vari'], 'price','name');
foreach($vari as $_k => $_v){
echo $_k.' '.$_v;
}
}
echo '<hr>';
}
}
结果:-
Shirt cotton shirt red 25.8green 26.5
shorts one size15.99
shoes black shoes capri 37.8shooters 28.5
Glax Red thin lightweight22.99
Bazoo Care ideal for winter32.99
答案 1 :(得分:0)
您快到了,只需要在第一个循环中输出密钥名称,所以
foreach ($data as $products) {
是在Specials
等项上循环的位。因此,首先抓住foreach()
中的键,然后将其作为循环中的第一件事输出...
foreach ($data as $key => $products) {
echo $key."<br>";
(否}
)
会给...
Specials<br>Shirt<br>cot...