OR

Question

我是一个完全的新手，正在尝试制作数字魔术。我希望程序在用户键入“否”时停止。这是我下面的代码！

 print("Hello and welcome to the number magic trick!!")
x = input("Yes or No")
if x == "Yes":
    print("Yay!!")
    print("Pick an integer number from 1 to 10 but don't tell me!")
    print("Multiply this number with 2")
    print("Multiply the new number by 5")
    print("Now, divide your current number with your original number")
    print("Subtract 7 from your current number")
    print("Is the answer 3 ?")
elif x == "No":
    print("Boo!!")
else:
    print("Invalid Input")

y = input ("Yes or No")
if y  == "Yes":
    print("Cool isn't it?")
elif y == "No":
    print("You can't do math!")
else:
    print("Invalid input")

Answer 1

您不必引发错误，只需使用exit方法即可。

if x.strip().lower() == "no":
  print("You said no!")
  exit(0)

您甚至可以使用exit模块中的sys方法，如下所示：

import sys

if x.strip().lower() == "no":
  print("You said no!")
  sys.exit(0)

信息：0方法中的exit表示“该程序已完成，没有任何错误” ，但替换了{{1 }}与0一起表示“程序出了点问题” ，并且退出并出现错误。

祝你好运。

Answer 2

您可以引发异常。另外，优良作法是将单行if / else语句放在同一行上。例如，

print("Hello and welcome to the number magic trick!!")
x = input("Yes or No")
if x == "Yes":
    print("Yay!!")
    print("Pick an integer number from 1 to 10 but don't tell me!")
    print("Multiply this number with 2")
    print("Multiply the new number by 5")
    print("Now, divide your current number with your original number")
    print("Subtract 7 from your current number")
    print("Is the answer 3 ?")
elif x == "No":
    print("Boo!!")
    raise SystemExit()
else:
    print("Invalid Input")
    raise SystemExit()

y = input ("Yes or No")
if y  == "Yes":
    print("Cool isn't it?")
elif y == "No":
    print("You can't do math!")
    raise SystemExit()
else:
    print("Invalid input")
    raise SystemExit()

欢迎您使用此代码...

Answer 3

if x == "No":
     quit()

OR

from sys import exit 
if x == "No":
     exit()

用户键入“否”时，如何停止程序？

3 个答案:

OR