Question

我每次点击按钮都需要花费一些时间来进行验证，以解决手动更改移动时间的问题。我需要一个从服务器获取日期并向我返回服务器日期的函数。

我尝试过了...

public static Date getCurrentDate() {

    final Date[] date = {null};
    RequestParams params = new RequestParams();

    HttpRestClient.postData(ApiManager.USER_TEAM_LIST, params, new AsyncHttpResponseHandler() {

        @Override
        public void onStart() {
            super.onStart();
        }

        @Override
        public void onFinish() {
            super.onFinish();
        }

        public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {
            String s = new String(responseBody);
            Log.e(TAG, "onSuccess: " + s);
            SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
            try {
                date[0] = format.parse(s);
            } catch (ParseException e) {
                e.printStackTrace();
            }

        }
        public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
            Log.e(TAG, "onFailure: getTeam" );
            /*Toast.makeText(mContext
                    , "Server Error...", Toast.LENGTH_SHORT).show();*/
        }
    });

   return date[0];
}

Answer 1

我刚刚找到了解决方案

//if your thread not accept than add this
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitNetwork().build();
        StrictMode.setThreadPolicy(policy);


static InetAddress inetAddress = null;
static TimeInfo timeInfo = null;

String TIME_SERVER = "time.google.com";

NTPUDPClient timeClient = new NTPUDPClient();

inetAddress = InetAddress.getByName(TIME_SERVER);
timeClient.open();
timeInfo = timeClient.getTime(inetAddress);

long returnTime = 0 ; 

if (timeInfo != null) {
      returnTime = timeInfo.getMessage().getTransmitTimeStamp().getTime();
}

我们如何在不使用任何后台线程的情况下获取服务器数据并在获取服务器数据后返回函数值

1 个答案: