Question

尝试查找我的用户模型时，我得到：对象可能为“ null” 如果可能的话，我宁愿不禁止打字稿的严格规定。

const { email, password } = req.body;
const user = await User.findOne({ email:email });
if (!user) {
}
/// This line causes the error
const passwordMatch = await bcrypt.compare(password, user.password);

////User Interface

import { Document } from 'mongoose';
interface User extends Document {
  email: string;
  password: string;
  username: string;
}
export default User;


////User Schema

import mongoose, { Document, Schema, Model, model } from 'mongoose';
import User from '../interfaces/User';

const UserSchema: Schema = new Schema({
  email: { type: String, required: true, unique: true },
  password: { type: String, required: true },
  username: { type: String, required: true },
});
export default mongoose.model<User>('User', UserSchema);

Answer 1

问题是，如果用户为null / undefined，则if语句public class ApiServices { public string JsonResult { get; private set; } public async Task<bool> RegisterUserAsync(string email, string name, /*string first_name, string last_name,*/ string password) { var client = new HttpClient(); var model = new RegisterBindingModel { Email = email, //FirstName = first_name, //LastName = last_name, Name = name, Password = password, }; var json = JsonConvert.SerializeObject(model); HttpContent httpContent = new StringContent(json); httpContent.Headers.ContentType = new MediaTypeHeaderValue("application/json"); var response = await client.PostAsync("https://myurl/v1/auth/register", httpContent); if (response.IsSuccessStatusCode) { var result = JsonConvert.DeserializeObject(JsonResult); return true; } return false; } public async Task<string> LoginAsync(string email, string password) { var keyValues = new List<KeyValuePair<string, string>> { new KeyValuePair<string, string>("email", email), new KeyValuePair<string, string>("password", password), new KeyValuePair<string, string>("grant_type", "password") }; var request = new HttpRequestMessage(HttpMethod.Post, "https://myurl/auth/login" + "Token"); request.Content = new FormUrlEncodedContent(keyValues); var client = new HttpClient(); var response = await client.SendAsync(request); var content = await response.Content.ReadAsStringAsync(); JObject jwtDynamic = JsonConvert.DeserializeObject<dynamic>(content); var accessTokenExpiration = jwtDynamic.Value<DateTime>(".expires"); var accessToken = jwtDynamic.Value<string>("access_token"); //Settings.AccessTokenExpirationDate = accessTokenExpiration; Debug.WriteLine(accessTokenExpiration); Debug.WriteLine(content); return accessToken; } }无法处理应该发生的情况。

如果用户选择null（或未定义），则选择从函数返回

if (!user)

TypeScript非常聪明，可以认识到一旦进入passwordMatch行，用户将永远不会为空

具有Typescript：Object的猫鼬可能为null

1 个答案: