我想创建具有多种类型用户的登录活动。此登录名与MySQL连接。多个选择是“审阅者”和“非审阅者”。现在,我使用Spinner和从string.xml调用的值。在“用户”表中,有一些列,例如“用户名”,“密码”和“用户类型”。例如,用户“ peter”是“审阅者”,如果他使用的用户名,密码和用户类型正确,他将能够登录。我怎么解决这个问题?下面是我的代码。
//登录活动 公共类MainActivity扩展了AppCompatActivity {
private static final String KEY_USERNAME = "username";
private static final String LOGIN_URL = "http://lienawan.xyz/login.php";
private SharedPreferences.Editor loginPrefsEditor;
private EditText etEmail;
private EditText etPassword;
private CheckBox chkMe;
ArrayAdapter<CharSequence> adapter;
@RequiresApi(api = Build.VERSION_CODES.KITKAT)
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE); //will hide the title
Objects.requireNonNull(getSupportActionBar()).hide(); // hide the title ba
setContentView(R.layout.activity_main);
etEmail = findViewById(R.id.etEmail);
etPassword = findViewById(R.id.etPassword);
chkMe = findViewById(R.id.chkMe);
SharedPreferences loginPreferences = getSharedPreferences("loginPrefs", MODE_PRIVATE);
loginPrefsEditor = loginPreferences.edit();
boolean saveLogin = loginPreferences.getBoolean("saveLogin", false);
if (saveLogin) {
etEmail.setText(loginPreferences.getString("username", ""));
etPassword.setText(loginPreferences.getString("password", ""));
chkMe.setChecked(true);
}
Spinner spCategory = findViewById(R.id.spCategory);
adapter = ArrayAdapter.createFromResource(this,R.array.usertype,android.R.layout.simple_spinner_item);
adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
spCategory.setAdapter(adapter);
spCategory.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
}
@Override
public void onNothingSelected(AdapterView<?> parent) {
}
});
Button btnLogin = findViewById(R.id.btnLogin);
btnLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
login();
InputMethodManager imm = (InputMethodManager) getSystemService(Context.INPUT_METHOD_SERVICE);
imm.hideSoftInputFromWindow(etEmail.getWindowToken(), 0);
String username = etEmail.getText().toString();
String password = etPassword.getText().toString();
if (chkMe.isChecked()) {
loginPrefsEditor.putBoolean("saveLogin", true);
loginPrefsEditor.putString("username", username);
loginPrefsEditor.putString("password", password);
loginPrefsEditor.apply();
} else {
loginPrefsEditor.clear();
loginPrefsEditor.commit();
}
}
});
}
@Override
public void onBackPressed() {
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Exit");
builder.setMessage("Do you want to exit?");
builder.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
finish();
}
});
builder.setNegativeButton("No", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
dialogInterface.cancel();
}
});
builder.show();
}
private void login() {
String username = etEmail.getText().toString().trim();
String password = etPassword.getText().toString().trim();
userLogin(username, password);
}
private void userLogin(final String username, final String password){
class UserLoginClass extends AsyncTask<String,Void,String> {
private ProgressDialog loading;
@Override
protected void onPreExecute() {
super.onPreExecute();
loading = ProgressDialog.show(MainActivity.this,"Login... Please Wait",null,true,true);
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
loading.dismiss();
if(s.equalsIgnoreCase("success")){
Intent intent = new Intent(MainActivity.this,DashboardApp.class);
intent.putExtra(KEY_USERNAME,username);
startActivity(intent);
}else{
Toast.makeText(MainActivity.this,s, Toast.LENGTH_LONG).show();
}
}
@Override
protected String doInBackground(String... params) {
HashMap<String,String> data = new HashMap<>();
data.put("username",params[0]);
data.put("password",params[1]);
Connection ruc = new Connection();
String result = ruc.sendPostRequest(LOGIN_URL,data);
return result;
}
}
UserLoginClass ulc = new UserLoginClass();
ulc.execute(username, password);
}
}
<?php
if($_SERVER['REQUEST_METHOD']=='POST'){
$username = $_POST['username'];
$password = $_POST['password'];
$approver = $_POST['approver'];
require_once('dbConnect.php');
$sql = "select * from user where username='$username' and password='$password'";
$check = mysqli_fetch_array(mysqli_query($con,$sql));
if(isset($check)){
echo "success";
}else{
echo "Invalid Username or Password";
}
}else{
echo "error try again";
答案 0 :(得分:1)
要从微调器中获取选定的值,请在onItemSelected
中编写以下代码:
String item;//declare globally out of your all method
@Override
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
// On selecting a spinner item
item = parent.getItemAtPosition(position).toString();
// Showing selected spinner item
Toast.makeText(parent.getContext(), "Selected: " + item, Toast.LENGTH_LONG).show();
}
现在,检查item
和其他值是否为not null
,如下所示:
private void login() {
String username = etEmail.getText().toString().trim();
String password = etPassword.getText().toString().trim();
//checking if fields are not null
if (username.isEmpty() || password.isEmpty() || item.isEmpty()) {
Toast.makeText(getActivity().getApplicationContext(), "Please enter name or pass or select one type!", Toast.LENGTH_SHORT).show();
return;
}else{
userLogin(username, password,item);//passing value to volley
}
}
在排球请求中进行如下更改:
private void userLogin(final String username, final String password,final String item){
...
@Override
protected String doInBackground(String... params) {
HashMap<String,String> data = new HashMap<>();
data.put("username",params[0]);
data.put("password",params[1]);
data.put("approver",params[2]);//adding item value
..
}
}
}
在您的PHP端,只需将query
更改为:
$sql = "select * from user where username='$username' and password='$password' and usertype='$approver'";
希望这对您有帮助!
注意 :也从未使用过plain-text password,尝试使用prepared statement是安全的。