Question

我想制作一个程序，它将带电并将其变成附加问题

main_number = int(input("Enter the number to be brought to the power "))
power = int(input("Enter the power "))

def get_num_of_final(power,number):
    yeet = pow(power,number-1)
    print(str(yeet))
    return(yeet)

def finall(number,multi):
    final = ""
    for i in range(multi):
        final += str(number)
        final += " + "
    print(final)

finall(main_number, get_num_of_final(power,main_number))

如果您输入2作为主电源，然后输入3作为电源，您应该得到2 + 2 + 2 + 2，但是您得到2 + 2 + 2 +或数字更大，您得到的结果将比预期的要高得多

Answer 1

result = main_number**power
print(f'{"+".join([str(main_number), ]*(result//main_number))} = {result}')

输出 2 + 2 + 2 + 2 = 8

Answer 2

您使用错误的参数致电pow；您需要：

yeet = pow(number, power-1)

新输出：

4
2 + 2 + 2 + 2 +

我如何获得幂并建立加法方程？

2 个答案: