Question

我需要在表中每个项目编号的每个-之间拉出字符串。

项目编号示例：

T-111459-DK-CAS-DGE-2X8-RT-M
T-1114659-MON-SKL-WT-3X9-GLS
T-111469-DK-PNN-GLZ-3X9-LE-GLS
T-111469-ARL-RIP-M-2X8-DUCR
T-111469-ARS-MAD-L-1X8-NL

以下是我想用第一个项目编号看到的内容：

在'-'＃1和'-'＃2之间是（111459）作为供应商
'-'＃2和'-'＃3之间的（DK）为线
在'-'＃3和'-'＃4之间的（CAS）为颜色

Answer 1

我尝试将其硬编码为：

declare @str varchar(100) = 'T-1114659-MON-SKL-WT-3X9-GLS' --testing purpose

select substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1) as Vendor
,substring(replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''),1,charindex('-',replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''))-1) as Line
, substring(reverse(substring(reverse(@str),1,len(@str)- len(substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1)) - len(substring(replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''),1,charindex('-',replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''))-1))-4)),1,CHARINDEX('-',reverse(substring(reverse(@str),1,len(@str)- len(substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1)) - len(substring(replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''),1,charindex('-',replace(@str,concat('T-',substring(substring(@str,3, len(@str)-2),1,charindex('-',substring(@str,3, len(@str)-2),1)-1),'-'),''))-1))-4)))-1) as Color

将@str替换为您的列名。祝你好运！

如何从表格中的项目中每次出现的“-”之间选择文本

1 个答案: