Question

我有一个像这样的数组

$chunk  = 4; 

$arr    = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');

我根据$chunk将此数组修改为行和列。在此示例中，它将是4x4的行和列。

我想做的是如何计算每列中有多少个“ 1”或“ 0”，并打印出“ 1”或“ 0”中最大的输出。

示例：

1110
1101
1110
1001

there are 4 number '1' in first column, so the output should be 4

我当前的代码：

function array_chunk_vertical($arr, $percolnum){
$n = count($arr);
$mod    = $n % $percolnum;
$cols   = floor($n / $percolnum);
$mod ? $cols++ : null ;
$re     = array();
for($col = 0; $col < $cols; $col++){
    for($row = 0; $row < $percolnum; $row++){
        if($arr){
            $re[$row][]   = array_shift($arr);
        }
    }
}
return $re;
}

$result = array_chunk_vertical($arr, $chunk);
$new    = 0;
$exist  = 0;

foreach($result  as $row){
    foreach($row as $val){
        if($val == "1"){
            $new++;
        }
        else{
            $exist++;
        }
            echo $val;          
    }
    echo '<br/>';
}

Answer 1

非常简短的代码段可以帮助您获得结果。

$i = 0;
foreach($result as $k => $v){
    $temp[$k] = count(array_filter(array_column($result,$i)));
    $i++;
}

在上面的代码中，array_column将从索引为0，索引为1等的所有数组中获取数据。
array_filter将删除0个值（默认性质）。
下面的输出包含所有垂直的第一个计数。

输出

Array
(
    [0] => 4
    [1] => 3
    [2] => 2
    [3] => 1
)

Demo

Answer 2

您可以按如下所示修改最后一个foreach循环来计算1和0列的计数

$columns = array();
 foreach($result  as $row){
   foreach($row as $key => $val){
    $columns[$key][] = $val;
    if($val == "1"){
        $new++;
    }
    else{
        $exist++;
    }
        echo $val;          
   }
  echo '<br/>';
 }

$cols = array_map(function($v){
   $temp = array_count_values($v);
   return 'Element :'.array_keys($temp, max($temp))[0].' came '.max($temp).' times.';
 }, $columns);

echo '<pre>';
print_r($cols);

结果

Array
(
 [0] => Element :1 came 4 times.
 [1] => Element :1 came 3 times.
 [2] => Element :1 came 2 times.
 [3] => Element :0 came 3 times.
)

Answer 3

我已经更新了块方法，以简化它，然后根据此结果，我使用array_column()和array_sum()的组合来加总每一列的总数。然后，您可以使用max()来找到最高价（代码中也有注释）...

$chunk  = 4;
$arr    = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');

function array_chunk_vertical($arr, $percolnum){
    $re = [];
    foreach ( $arr as $number => $value )   {
        // Use modulus % to put value in correct column
        $re [$number % $percolnum][] = $value;
    }
    return $re;
}
$result = array_chunk_vertical($arr, $chunk);

$count = [];
// Loop over first row of output
foreach($result[0]  as $column => $row){
    // Sum up the results of taking all the column values for this column
    $count[$column] = array_sum(array_column($result, $column));
}
// Extract highest
$highest = max($count);
// Find highest and output which one it is.
echo $highest ." in ". (array_search($highest, $count)+1);

产生

4 in 1

Answer 4

$chunk  = 4; 
$arr    = array('1', '1', '1', '1', '1', '1', '1', '0', '1', '0', '1', '0', '0', '0', '0', '1');

// Split your array in chunks
$chunks = array_chunk($arr, 4);
// Max counts for 1 and 0 
$max1 = $max0 = 0;
foreach ($chunks as $chunk) {
    // count number of occurences of 1 and 0
    $countedValues = array_count_values($chunk);
    $cur1 = isset($countedValues[1]) ? $countedValues[1] : 0;
    $cur0 = isset($countedValues[0]) ? $countedValues[0] : 0;

    echo 'count 1 is ' . $cur1 . PHP_EOL;
    echo 'count 0 is ' . $cur0 . PHP_EOL;

    $max1 = max($max1, $cur1);
    $max0 = max($max0, $cur0);
}

echo '1 max count is ' . $max1 . PHP_EOL . '0 max count is ' . $max0;

如何计算每列的数组值？

4 个答案: