Question

我有一个这样的架构：

create table AppUser (id int, name varchar(255));
insert into AppUser (id, name) values ('1','sashan');
insert into AppUser (id, name) values ('2','someone');
insert into AppUser (id, name) values ('3','mckenzie');
create table school (id int, name varchar(255));
insert into School (id, name) values ('1','pascoe high');
insert into School (id, name) values ('2','highbury');
insert into School (id, name) values ('3','hilton');
insert into School (id, name) values ('4','melbourne girls');
create table Student(SchoolId int, UserId int);
insert into Student (SchoolId, UserId) values ('2','1');
insert into Student (SchoolId, UserId) values ('3','1');
insert into Student (SchoolId, UserId) values ('4','3');

AppUser表是用户信息。 School表是学校信息。学生表将学校与用户链接起来。我想选择所有不包含“ sashan”的学校。

我想出了这个

select *
from School
left join Student
       on Student.SchoolId = School.Id
left join AppUser
       on AppUser.id = Student.userid
where AppUser.name is null
   or AppUser.name != 'sashan';

但是想知道是否还有更好的方法。

如果您想重现该表并使用此问题中的代码测试sql，请参见http://www.sqlfiddle.com/

Answer 1

您可以尝试以下方法：

SELECT *
FROM   School
WHERE  id NOT IN (SELECT SchoolId
                  FROM   Student
                  JOIN   AppUser
                    ON   Student.UserId = AppUser.id
                   AND   name = 'sashan')

方括号之间的查询选择所有学校“ sashan”在其中。
选择所有不属于这些学校的学校，即可得到您所要求的学校。

Answer 2

我会使用not exists：

select s.*
from School s 
where not exists (select 1
                  from Student st join
                       AppUser au
                       on au.id = st.userid
                  where st.SchoolId = s.Id and
                        au.name = 'sashan' 
                 );

您的版本不太正确，因为'sashan'上的条件必须在on子句中。因此，与上述等效：

select s.*
from School s left join
     Student st
     on st.SchoolId = s.Id left join
     AppUser au
     on au.id = st.userid and au.name = 'sashan'
where au.name is null;

Answer 3

您做对了。这是使用NOT EXISTS原因的替代版本

SELECT s.*
FROM school s
WHERE NOT EXISTS 
  (SELECT 1 
   FROM student st 
   JOIN AppUser au ON au.name != 'sashan' AND au.id = st.userId 
   WHERE s.id = st.schoolId)

如果索引正确，那么这两个查询应该都能很好地工作

选择不在多个联接语句创建的表中的行

3 个答案: