Question

我在Laravel中有2个Collections，我只想在$result对象中使用通用值。我看到$collection->intersect()仅适用于一维数组。以下是收藏集

Collection {#1086 ▼
  #items: array:5 [▼
    0 => {#1115 ▼
      +"name": "Light"
      +"class": "ABC"
      +"id": 4
    }
    1 => {#1113 ▼
      +"name": "Milo"
      +"class": "XYZ"
      +"id": 10
    }
    2 => {#1120 ▼
      +"name": "Milo Test"
      +"class": "ABC"
      +"id": 12
    }
    3 => {#1102 ▼
      +"name": "KMSMiloCow"
      +"class": "ABC"
      +"id": 16
    }
    4 => {#1106 ▼
      +"name": "MiloCows"
      +"class": "XYZ"
      +"id": 18
    }
  ]
}

Collection {#1086 ▼
      #items: array:5 [▼
        0 => {#1115 ▼
          +"name": "Light"
          +"class_name": "ABC"
          +"id": 4
        }           
      ]
    }

现在，我只需要这个

Collection {#1086 ▼
          #items: array:5 [▼
            0 => {#1115 ▼
              +"name": "Light"
              +"class": "ABC"
              +"id": 4
            }           
          ]
        }

Answer 1

我认为使用收集方法each和contains，可以像这样

    $collection1->each(function ($value, $key) use ($collection2){
        return $collection2->contains($value);
    });
    dd($collection1);

我在路由文件web.php中对其进行测试

use Illuminate\Support\Collection;
Route::get('test', function(){
    $collection1 = new Collection([
        'bear',
        'whale',
        'chicken',
        'tardigrade'
    ], [[
        'bear8',
        'whale44',
        'chicken45',
        'tardigrade445'
    ]]);
    $collection2 = new Collection([
        'bear1',
        'whale2',
        'chicken3',
        'tardigrade4'
    ], [[
        'bear',
        'whale',
        'chicken',
        'tardigrade'
    ]]);
    $collection1->each(function ($value, $key) use ($collection2){
        return $collection2->contains($value);
    });
    dd($collection1);
});

Answer 2

尝试

 $a1 = array(
           array('name' => 'asdfjkl;', 'class' => 'foo'),
           array('name' => 'qwerty', 'class' => 'bar'),
           array('name' => 'uiop', 'class' => 'baz'),
        );
$a2 = array(
           array('name' => 'asdfjklk;', 'class' => 'foo'),
           array('name' => 'qwertyxs', 'class' => 'bar'),
           array('name' => 'uiop', 'class' => 'baz'),
        );
$cc = array_uintersect($a1, $a2, 'cmp');
print_r($cc);

function cmp($a1, $a2){
   return strcasecmp($a1['name'] , $a2['name']);
}

Answer 3

我不知道这对您有没有帮助，但是这些会有用

replace(/<a href="(.*)"/g, '<a href="$1/index.html"')

Answer 4

要获取包含公共元素的集合，您可以使用 filter():

<块引用>

filter 方法使用给定的回调过滤集合，只保留那些通过给定真值测试的项目

$commonCollection = $collection1->filter(function ($value, $key) use ($collection2){
    return $collection2->contains($value);
});

如何从2个Laravel集合中获取共同值

4 个答案: